在php中将复选框值从一个页面传递到另一个页面
如何在PHP中将复选框值从一个页面发送到另一个页面？复选框值是从数据库中提取的。我需要将选中的值从一个页面发送到另一个页面。我是php新手 page1.php在php中将复选框值从一个页面传递到另一个页面,php,html,sql,Php,Html,Sql,如何在PHP中将复选框值从一个页面发送到另一个页面？复选框值是从数据库中提取的。我需要将选中的值从一个页面发送到另一个页面。我是php新手 page1.php <form method="post" action="setupstates.php"> <table border=".3px" id='acttable'> <tr> <td><b>Act Name</b></td>
<form method="post" action="setupstates.php">
<table border=".3px" id='acttable'>
<tr>
<td><b>Act Name</b></td>
<td colspan="5"><input type='text' name="actname" size="130" required></td>
</tr>
<tr>
<td><b>Industry Type</b></td>
<td colspan="5"><input type="checkbox">
Select All Industries</td>
<?php
$conn = get_dbconnect();
$sql1 = "SELECT*FROM industry";
$result = mysqli_query($conn, $sql1);
$nrows = mysqli_num_rows($result);
//echo $nrows;
$sql = "SELECT name FROM industry"; //selection query
$rs = mysqli_query($conn, $sql); //odbc_exec($conn,$sql);
// if(mysqli_num_rows($rs)>0){
while ($nrows > 0) {
echo "<tr>";
for ($i = 0; $i < 5; $i++) {
$row = mysqli_fetch_assoc($rs);
echo "<td><input type='checkbox' name='industrytype' value='" . $row['name'] . "'/>" . $row['name'];
}
$nrows = $nrows - 5;
echo '</tr>';
}
?>
</tr>
</table>
<input type="submit">
</form>
艺名
行业类型
选择所有行业
行业类型
您正在传递多个复选框值，而不是一个。这意味着您的setupdstates.php需要是一个循环来处理所有值
请注意，复选框很奇怪。如果不进行检查，则不会向PHP发送任何内容。因此，您将只获得已检查的
<?php //page1.php ?>
<form method="post" action="setupstates.php">
<table border=".3px" id='acttable'>
<tr>
<td><b>Act Name</b></td>
<td colspan="5"><input type='text' name="actname" size="130" required></td>
</tr>
<tr>
<td><b>Industry Type</b></td>
<td colspan="5"><input type="checkbox">Select All Industries</td>
<?php
$conn = get_dbconnect();
$sql1 = "SELECT * FROM industry";
$result = mysqli_query($conn, $sql1);
$nrows = mysqli_num_rows($result);
//echo $nrows;
$sql= "SELECT name FROM industry"; //selection query
$rs = mysqli_query($conn, $sql);//odbc_exec($conn,$sql);
// if(mysqli_num_rows($rs)>0){
$n = 0;
while( $nrows > 0 ) {
echo "<tr>";
for($i=0; $i < 5; $i++) {
$row = mysqli_fetch_assoc($rs);
//
echo "<td><input type='checkbox' name='industrytype[]' value='".$row['name']."' onclick=checkall();/>".$row['name'] . "</td>";
}
$nrows = $nrows-5;
echo '</tr>';
}
?>
</tr>
</table>
<?php // setupstates.php ?>
<table>
<?php foreach ($_POST["industrytype"] as $value) : ?>
<tr>
<td><b>Industry Type</b></td>
<td>
<input type="checkbox" value="<?php print $value; ?>">
</td>
</tr>
<?php endforeach; ?>
</table>
艺名
行业类型
选择所有行业
行业类型
试试这个。它会对你有用的
page1.php
<form method="post" action="setupstates.php">
<table border=".3px" id='acttable'>
<tr>
<td><b>Act Name</b></td>
<td colspan="5"><input type='text' name="actname" size="130" required></td>
</tr>
<tr>
<td><b>Industry Type</b></td>
<td colspan="5"><input type="checkbox">
Select All Industries</td>
<?php
$conn = get_dbconnect();
$sql1 = "SELECT*FROM industry";
$result = mysqli_query($conn, $sql1);
$nrows = mysqli_num_rows($result);
//echo $nrows;
$sql = "SELECT name FROM industry"; //selection query
$rs = mysqli_query($conn, $sql); //odbc_exec($conn,$sql);
// if(mysqli_num_rows($rs)>0){
while ($nrows > 0) {
echo "<tr>";
for ($i = 0; $i < 5; $i++) {
$row = mysqli_fetch_assoc($rs);
echo "<td><input type='checkbox' name='industrytype[]' value='" . $row['name'] . "'/>" . $row['name'];
}
$nrows = $nrows - 5;
echo '</tr>';
}
?>
</tr>
<tr><td colspan="5"><input type="submit" name="submit" value="submit"></td></tr>
</table>
<input type="submit">
</form>
setupstates.php
<?php
if($_POST){
$chk = array();
$chk = $_POST['industrytype'];
$total = count($chk);
for($i=0; $i<$total; $i++){?>
<input type="checkbox" checked="checked" value="<?php echo $chk[$i] ?>"><?php echo $chk[$i]?>
<?php}}?>
page1.php
艺名
行业类型
选择所有行业
setupstates.php
此代码确实有效：-
创建第一页-index.php
form action=“process.php”method=“post”>
选择您的兴趣：
JAVA
PHP
python
JavaScript
提交
创建第二个页面-Process.php
课程：
输出：-课程：Java-PHP-Python-JavaScript在setupstates中命名为数组industrytype[]使用$\u POST['industrytype']获取值page1中的submit按钮在哪里。phpafter标记am使用submit按钮。其内部格式仅打印（$\u POST）；在setupstates.php文件上，并在此处打印您得到了什么？为什么要使用$nrows=$nrows-5？$nrows=$nrows-5；有什么用？总计有18个复选框值，使用$nrow在每行am中显示5个复选框值$nrow仅用于对齐此答案是否有您不喜欢的地方？我只想将选中的值传递到另一页$\u POST[“行业类型”]包含上一页的所有选中值。
page1.php
<form method="post" action="setupstates.php">
<table border=".3px" id='acttable'>
<tr>
<td><b>Act Name</b></td>
<td colspan="5"><input type='text' name="actname" size="130" required></td>
</tr>
<tr>
<td><b>Industry Type</b></td>
<td colspan="5"><input type="checkbox">
Select All Industries</td>
<?php
$conn = get_dbconnect();
$sql1 = "SELECT*FROM industry";
$result = mysqli_query($conn, $sql1);
$nrows = mysqli_num_rows($result);
//echo $nrows;
$sql = "SELECT name FROM industry"; //selection query
$rs = mysqli_query($conn, $sql); //odbc_exec($conn,$sql);
// if(mysqli_num_rows($rs)>0){
while ($nrows > 0) {
echo "<tr>";
for ($i = 0; $i < 5; $i++) {
$row = mysqli_fetch_assoc($rs);
echo "<td><input type='checkbox' name='industrytype[]' value='" . $row['name'] . "'/>" . $row['name'];
}
$nrows = $nrows - 5;
echo '</tr>';
}
?>
</tr>
<tr><td colspan="5"><input type="submit" name="submit" value="submit"></td></tr>
</table>
<input type="submit">
</form>
setupstates.php
<?php
if($_POST){
$chk = array();
$chk = $_POST['industrytype'];
$total = count($chk);
for($i=0; $i<$total; $i++){?>
<input type="checkbox" checked="checked" value="<?php echo $chk[$i] ?>"><?php echo $chk[$i]?>
<?php}}?>