Php 有人能帮我理解这个数组吗？

为什么

J

的工作方式是0,2,4,1,3，而不是0,1,2,3,4，任何人都可以帮忙？

$data1 = ["Monday","08:00","10:00","15:00","16:00","Tuesday","08:00","10:00","18:00","21:00","Monday","11:00","12:00","17:00","20:00","Tuesday","10:00","13:00","17:00","20:00","Monday","06:00","07:00","16:00","18:00"];
$data2 = [ "Monday","08:00","09:00","18:00","20:00","Tuesday","08:00","09:00","--","--"];

$data1_chunk = array_chunk($data1,5);
$data2_chunk = array_chunk($data2,5);


for($i=0;$i<count($data2_chunk);$i++){
    for($j=0;$j<count($data1_chunk);$j++){
        if($data1_chunk[$j][0] == $data2_chunk[$i][0]){
            echo "J=>".$j."I=>".$i."\n";
        }
    }
}

---

array chunk所做的是将一个大数组拆分为一个小数组，例如：

$array=[“测试1”、“测试2”、“测试3”、“测试4”、“测试5”]；
$output=array\u chunk（$array，2）；
变量转储（输出）；

分块数组将如下所示：

[
    ["test 1", "test 2"],
    ["test 3", "test 4"],
    ["test 5"],
]

---

如果将输出更改为“

echo”J=>”$data1\u chunk[$J][0]。“I=>”$data2\u chunk[$I][0]。“\n”你可以看到它匹配的数据。我不想做任何事情，我只是想知道为什么J会像0,2,4,1,3那样递增。不是的，只是你在第二个数组日（星期一和星期二）循环，并打印出第一个数组中匹配的位置（星期一是0,2,4，星期二是位置1和3）。
[
    ["test 1", "test 2"],
    ["test 3", "test 4"],
    ["test 5"],
]