Php 正确格式的laravel数据结果集
我正在使用laravel制作一个API,用于查询数据库并显示一个简单的输出。现在我的问题是这样的:Php 正确格式的laravel数据结果集,php,json,laravel,Php,Json,Laravel,我正在使用laravel制作一个API,用于查询数据库并显示一个简单的输出。现在我的问题是这样的: $name = new TableName() ; //An object which is storing tablename $result=DB::table($name->getMyTableName()) // Getting the tablename ->select() ->where('id','=',1)->orWhere
$name = new TableName() ; //An object which is storing tablename
$result=DB::table($name->getMyTableName()) // Getting the tablename
->select()
->where('id','=',1)->orWhere('id','=',2)
->get();
[
{
"id": "1",
"question": "This is",
"question_main": "sample1",
"option_1": "opt_1",
"option_2": "opt_1",
"option_3": "opt_1",
"option_4": "opt_1",
},
{
"id": "2",
"question": "This is",
"question_main": "sample2",
"option_1": "opt_1",
"option_2": "opt_2",
"option_3": "opt_3",
"option_4": "opt_4",
}
]
现在,这将获取id为1和2的两条记录,当我通过控制器传递它们时,json输出如下:
$name = new TableName() ; //An object which is storing tablename
$result=DB::table($name->getMyTableName()) // Getting the tablename
->select()
->where('id','=',1)->orWhere('id','=',2)
->get();
[
{
"id": "1",
"question": "This is",
"question_main": "sample1",
"option_1": "opt_1",
"option_2": "opt_1",
"option_3": "opt_1",
"option_4": "opt_1",
},
{
"id": "2",
"question": "This is",
"question_main": "sample2",
"option_1": "opt_1",
"option_2": "opt_2",
"option_3": "opt_3",
"option_4": "opt_4",
}
]
现在我想要的不是选项,而是这样的:
$name = new TableName() ; //An object which is storing tablename
$result=DB::table($name->getMyTableName()) // Getting the tablename
->select()
->where('id','=',1)->orWhere('id','=',2)
->get();
[
{
"id": "1",
"question": "This is",
"question_main": "sample1",
"option_1": "opt_1",
"option_2": "opt_1",
"option_3": "opt_1",
"option_4": "opt_1",
},
{
"id": "2",
"question": "This is",
"question_main": "sample2",
"option_1": "opt_1",
"option_2": "opt_2",
"option_3": "opt_3",
"option_4": "opt_4",
}
]
选项:
{
1=>"opt_1",
2=>"opt_2",
3=>"opt_3",
4=>"opt_4",
}
现在我尝试的是:
foreach ($result as $results)
{
$final_result= array_add($final_result, 'id', $results->id);
$final_result= array_add($final_result, 'question', $results->question);
$final_result= array_add($final_result, 'question_main', $results->question_main);
$final_result= array_add($final_result, 'options', array(
[
1 => $results->option_1,
2 => $results->option_2,
3 => $results->option_3,
4 => $results->option_4,
]
));
}
return json_encode($final_result,JSON_PRETTY_PRINT);
不过,这基本上解决了这个问题,因为您可能已经发现键值对可以有唯一的键,所以它只存储id=2(后者)。我很困惑接下来该做什么。我尝试了多维数组,但我认为我无法正确理解这个概念。任何建议,请提前感谢您可以使用foreach中的键执行以下操作:
$final_result = [];
foreach ($result as $key => $results)
{
$final_result[$key] = [
'id' => $results->id,
'question' => $results->question,
'question_main' => $results->question_main,
'options' => [
1 => $results->option_1,
2 => $results->option_2,
3 => $results->option_3,
4 => $results->option_4
]
];
}
return json_encode($final_result,JSON_PRETTY_PRINT);
这将达到预期效果
$arrayToBePrinted = [];
foreach ($result as $results)
{
$final_result= array_add($final_result, 'id', $results->id);
$final_result= array_add($final_result, 'question', $results->question);
$final_result= array_add($final_result, 'question_main', $results->question_main);
$final_result= array_add($final_result, 'options', array(
[
1 => $results->option_1,
2 => $results->option_2,
3 => $results->option_3,
4 => $results->option_4,
]
));
$arrayToBePrinted[] = $final_result;
}
return json_encode($arrayToBePrinted,JSON_PRETTY_PRINT);
这是当场的。非常感谢:)您在我被卡住的地方犯了同样的错误,$ARRAYTOBEPRINT将只存储最后一个id,并只显示两次,无论如何,感谢您的帮助:)
$ARRAYTOBEPRINT[]
将向其追加$final\u result
。因此,它应该按照伊万卡托罗娃所说的那样起作用。它是附加的,所以应该可以工作。我做了检查,它向我显示了相同的东西两次,我仍然会再次检查,并会让你知道。