Php 连接2个mysql查询
我有两张桌子： 用户 id |用户 喜欢 id |所有者|日期 此查询：Php 连接2个mysql查询,php,mysql,sql,Php,Mysql,Sql,我有两张桌子： 用户 id |用户 喜欢 id |所有者|日期 此查询： $owner_result = $connector->query("SELECT id FROM users"); while($owner = $connector->fetchArray($owner_result)) { $rs = $connector->query("SELECT count(id) AS num FROM likes WHERE date > DATE_SUB(NOW
$owner_result = $connector->query("SELECT id FROM users");
while($owner = $connector->fetchArray($owner_result))
{
$rs = $connector->query("SELECT count(id) AS num FROM likes
WHERE date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
AND owner='$owner[id]'
ORDER BY num DESC LIMIT 5");
while($rw = $connector->fetchArray($rs))
{echo "This owner ($owner[id]) has $rw[num] likes this week";}
}
谢谢。您必须在第二个查询中按所有者分组。如果不先对行进行分组，则无法对行进行计数
$owner_result = $connector->query("SELECT id FROM users");
while($owner = $connector->fetchArray($owner_result))
{
$rs = $connector->query("SELECT count(id) AS num FROM likes
WHERE date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
AND owner='$owner[id]'
Group BY owner
ORDER BY num DESC LIMIT 5");
while($rw = $connector->fetchArray($rs))
{echo "This owner ($owner[id]) has $rw[num] likes this week";}
}
您必须在第二个查询中按所有者分组。如果不先对行进行分组，则无法对行进行计数
$owner_result = $connector->query("SELECT id FROM users");
while($owner = $connector->fetchArray($owner_result))
{
$rs = $connector->query("SELECT count(id) AS num FROM likes
WHERE date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
AND owner='$owner[id]'
Group BY owner
ORDER BY num DESC LIMIT 5");
while($rw = $connector->fetchArray($rs))
{echo "This owner ($owner[id]) has $rw[num] likes this week";}
}
您必须在第二个查询中按所有者分组。如果不先对行进行分组，则无法对行进行计数
$owner_result = $connector->query("SELECT id FROM users");
while($owner = $connector->fetchArray($owner_result))
{
$rs = $connector->query("SELECT count(id) AS num FROM likes
WHERE date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
AND owner='$owner[id]'
Group BY owner
ORDER BY num DESC LIMIT 5");
while($rw = $connector->fetchArray($rs))
{echo "This owner ($owner[id]) has $rw[num] likes this week";}
}
您必须在第二个查询中按所有者分组。如果不先对行进行分组，则无法对行进行计数
$owner_result = $connector->query("SELECT id FROM users");
while($owner = $connector->fetchArray($owner_result))
{
$rs = $connector->query("SELECT count(id) AS num FROM likes
WHERE date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
AND owner='$owner[id]'
Group BY owner
ORDER BY num DESC LIMIT 5");
while($rw = $connector->fetchArray($rs))
{echo "This owner ($owner[id]) has $rw[num] likes this week";}
}
您应该连接两个表，以便在一条语句中获取数据：
SELECT
users.id,
COUNT(likes.id) AS mylikes -- specify a name for the computed column
FROM users
INNER JOIN likes
ON users.id = likes.owner
WHERE date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY users.id
ORDER BY COUNT(likes.id) DESC -- MySQL would allow the alias name
LIMIT 5 -- because you want the top 5
如果出现平局，则您将丢失一条（或多条）记录。您应该将两个表合并，以便在一条语句中获取数据：
SELECT
users.id,
COUNT(likes.id) AS mylikes -- specify a name for the computed column
FROM users
INNER JOIN likes
ON users.id = likes.owner
WHERE date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY users.id
ORDER BY COUNT(likes.id) DESC -- MySQL would allow the alias name
LIMIT 5 -- because you want the top 5
如果出现平局，则您将丢失一条（或多条）记录。您应该将两个表合并，以便在一条语句中获取数据：
SELECT
users.id,
COUNT(likes.id) AS mylikes -- specify a name for the computed column
FROM users
INNER JOIN likes
ON users.id = likes.owner
WHERE date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY users.id
ORDER BY COUNT(likes.id) DESC -- MySQL would allow the alias name
LIMIT 5 -- because you want the top 5
如果出现平局，则您将丢失一条（或多条）记录。您应该将两个表合并，以便在一条语句中获取数据：
SELECT
users.id,
COUNT(likes.id) AS mylikes -- specify a name for the computed column
FROM users
INNER JOIN likes
ON users.id = likes.owner
WHERE date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY users.id
ORDER BY COUNT(likes.id) DESC -- MySQL would allow the alias name
LIMIT 5 -- because you want the top 5
如果出现平局，那么您将丢失一条（或更多）记录。我认为单次查询将获得指定的结果，例如：
SELECT u.id
, COUNT(t.owner) AS cnt_likes
FROM users u
JOIN likes t
ON t.owner = u.id
WHERE t.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY u.id
ORDER BY 2 DESC
LIMIT 5
likes... ON likes (owner, date)
SELECT u.id
, t.cnt_likes
FROM users u
JOIN ( SELECT s.owner
, COUNT(1) AS cnt_likes
FROM likes s
WHERE s.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY s.owner
) t
ON t.owner = u.id
ORDER BY t.cnt_likes DESC
LIMIT 5
... ON likes (owner, date)
SELECT u.id
, t.cnt_likes
FROM users u
JOIN ( SELECT s.owner
, COUNT(1) AS cnt_likes
FROM likes s
WHERE s.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY s.owner
) t
ON t.owner = u.id
ORDER BY t.cnt_likes DESC
LIMIT 5
如果保证
likesowneruseridlikesSELECT s.owner
, COUNT(1) AS cnt_likes
FROM likes s
WHERE s.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY s.owner
ORDER BY cnt_likes DESC
LIMIT 5
但是，该查询不会进行检查，以验证从
owneruseridSELECT u.id
, COUNT(t.owner) AS cnt_likes
FROM users u
JOIN likes t
ON t.owner = u.id
WHERE t.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY u.id
ORDER BY 2 DESC
LIMIT 5
likes... ON likes (owner, date)
SELECT u.id
, t.cnt_likes
FROM users u
JOIN ( SELECT s.owner
, COUNT(1) AS cnt_likes
FROM likes s
WHERE s.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY s.owner
) t
ON t.owner = u.id
ORDER BY t.cnt_likes DESC
LIMIT 5
... ON likes (owner, date)
SELECT u.id
, t.cnt_likes
FROM users u
JOIN ( SELECT s.owner
, COUNT(1) AS cnt_likes
FROM likes s
WHERE s.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY s.owner
) t
ON t.owner = u.id
ORDER BY t.cnt_likes DESC
LIMIT 5
如果保证
likesowneruseridlikesSELECT s.owner
, COUNT(1) AS cnt_likes
FROM likes s
WHERE s.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY s.owner
ORDER BY cnt_likes DESC
LIMIT 5
但是，该查询不会进行检查，以验证从
owneruseridSELECT u.id
, COUNT(t.owner) AS cnt_likes
FROM users u
JOIN likes t
ON t.owner = u.id
WHERE t.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY u.id
ORDER BY 2 DESC
LIMIT 5
likes... ON likes (owner, date)
SELECT u.id
, t.cnt_likes
FROM users u
JOIN ( SELECT s.owner
, COUNT(1) AS cnt_likes
FROM likes s
WHERE s.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY s.owner
) t
ON t.owner = u.id
ORDER BY t.cnt_likes DESC
LIMIT 5
... ON likes (owner, date)
SELECT u.id
, t.cnt_likes
FROM users u
JOIN ( SELECT s.owner
, COUNT(1) AS cnt_likes
FROM likes s
WHERE s.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY s.owner
) t
ON t.owner = u.id
ORDER BY t.cnt_likes DESC
LIMIT 5
如果保证
likesowneruseridlikesSELECT s.owner
, COUNT(1) AS cnt_likes
FROM likes s
WHERE s.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY s.owner
ORDER BY cnt_likes DESC
LIMIT 5
但是，该查询不会进行检查，以验证从
owneruseridSELECT u.id
, COUNT(t.owner) AS cnt_likes
FROM users u
JOIN likes t
ON t.owner = u.id
WHERE t.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY u.id
ORDER BY 2 DESC
LIMIT 5
likes... ON likes (owner, date)
SELECT u.id
, t.cnt_likes
FROM users u
JOIN ( SELECT s.owner
, COUNT(1) AS cnt_likes
FROM likes s
WHERE s.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY s.owner
) t
ON t.owner = u.id
ORDER BY t.cnt_likes DESC
LIMIT 5
... ON likes (owner, date)
SELECT u.id
, t.cnt_likes
FROM users u
JOIN ( SELECT s.owner
, COUNT(1) AS cnt_likes
FROM likes s
WHERE s.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY s.owner
) t
ON t.owner = u.id
ORDER BY t.cnt_likes DESC
LIMIT 5
如果保证
likesowneruseridlikesSELECT s.owner
, COUNT(1) AS cnt_likes
FROM likes s
WHERE s.date > DATE_SUB(NOW(), INTERVAL 1 WEEK)
GROUP BY s.owner
ORDER BY cnt_likes DESC
LIMIT 5
但是，该查询不会进行检查，以验证从
owneruserid