Php 如何通过循环中的关系获取所有用户

我收集了很多喜欢的东西。每个like都有一个属于->用户关系。 如何获取所有用户。目前我只得到一个用户

$likes = Like::where('thought_id', $thoughtComment->thought_id)->where('comment_id', $thoughtComment->id)->where('like_flag', 1)->get();


        foreach($likes as $like){
            $users = $like->user->username ?? '';
        }

        return $users;

---

好的。让我们从您拥有的位置开始：

$likes = Like::where('thought_id', $thoughtComment->thought_id)->where('comment_id', $thoughtComment->id)->where('like_flag', 1)->get();
    foreach($likes as $like){
        $users = $like->user->username ?? '';
    }

    return $users;

接下来，让我们修复构建数组所需的内容，而不是一直覆盖相同的标量值

$likes = Like::where('thought_id', $thoughtComment->thought_id)
    ->where('comment_id', $thoughtComment->id)
    ->where('like_flag', 1)->get();
$users = array(); //Users needs to be an empty array.

foreach($likes as $like){
    $users[] = $like->user->username ?? ''; // We append to it.
}

return $users;

但我们可以做得更好，因为这将执行嵌套查询。因此，让我们用

和
将用户加载到like中，我们可以循环使用它

$like = Like::where('thought_id', $thoughtComment->thought_id)
    ->where('comment_id', $thoughtComment->id)
    ->where('like_flag', 1)
    ->with([ // Eager the relationships we'll use
        'user' => function($query){
             $query->select('user.username'); 
             //But really, we only need the username
        }
    ])->get();

foreach($likes as $like){
    $users[] = $like->user->username ?? ''; // We append to it.
}

return $users;

然后使用集合的展平和拾取功能，这样我们就不必编写循环

$like = Like::where('thought_id', $thoughtComment->thought_id)
    ->where('comment_id', $thoughtComment->id)
    ->where('like_flag', 1)
    ->with([
        'user' => function($query){
          $query->select('user.username');
        }
    ])->get();

//Lets get rid of the loop altogether and let the collection do the work.
$users = $like->flatten()->pluck('username');

$users[]=$like->user->username？？”-不要忘记在循环之前初始化数组。你也可以省略没有用户名的用户，但这取决于你自己。谢谢。我也不会忘记急切地加载这个关系来解决这个循环的n+1问题<代码>类似：：with（'user'）->其中（'think_id…）