php：对给定字符串中的单词实例进行排序和计数

我需要帮助排序和计算字符串中的单词实例

假设我有一个单词集：

快乐美丽快乐线条梨子杜松子酒快乐线条摇滚快乐线条梨子

如何使用php计算字符串中每个单词的每个实例并将其输出到循环中：

There are $count instances of $word

这样，上述循环将输出：

有4个快乐的例子

有3个线的实例

杜松子酒有两个例子

结合使用和：

给予

str\u word\u count（）

中的

1

使函数返回所有找到的单词的数组

要对条目进行排序，请使用（保留键）：

试试这个：

$words = explode(" ", "happy beautiful happy lines pear gin happy lines rock happy lines pear");
$result = array_combine($words, array_fill(0, count($words), 0));

foreach($words as $word) {
    $result[$word]++;
}

foreach($result as $word => $count) {
    echo "There are $count instances of $word.\n";
}

结果:

There are 4 instances of happy.
There are 1 instances of beautiful.
There are 3 instances of lines.
There are 2 instances of pear.
There are 1 instances of gin.
There are 1 instances of rock. 

---

我怎么能把这个和重音词连用呢？例子：太简单了！；）谢谢@syfantid是的，你说得很好，不需要其他答案；）

arsort($words);
print_r($words);

Array
(
    [happy] => 4
    [lines] => 3
    [pear] => 2
    [rock] => 1
    [gin] => 1
    [beautiful] => 1
)

$words = explode(" ", "happy beautiful happy lines pear gin happy lines rock happy lines pear");
$result = array_combine($words, array_fill(0, count($words), 0));

foreach($words as $word) {
    $result[$word]++;
}

foreach($result as $word => $count) {
    echo "There are $count instances of $word.\n";
}

There are 4 instances of happy.
There are 1 instances of beautiful.
There are 3 instances of lines.
There are 2 instances of pear.
There are 1 instances of gin.
There are 1 instances of rock.