存在密钥时phpredis rpop返回false
我正在构建一个使用redis的游戏应用程序,这是我的php脚本存在密钥时phpredis rpop返回false,php,redis,phpredis,Php,Redis,Phpredis,我正在构建一个使用redis的游戏应用程序,这是我的php脚本 <?php //melon game pop //connect to redis db $redis = new Redis(); $redis->connect('127.0.0.1', 6379); //receive the data as json //$data = json_decode(file_get_contents('php://input'), true); $data = null;
<?php
//melon game pop
//connect to redis db
$redis = new Redis();
$redis->connect('127.0.0.1', 6379);
//receive the data as json
//$data = json_decode(file_get_contents('php://input'), true);
$data = null;
//decided to just grab the string
$key = file_get_contents('php://input');
//Shotgun debugging in action
$my_key = trim($key);
/*
was originally sending json on reading into variables from array decided to simplify until my issue is resolved
//parse my data in to separate variables
if ($data != null) {
$key = $data['key'];
//$value = $data['value'];
//$key = utf8_decode($key);
}
else
{
print "It's not recognizing your data!";
}
*/
$my_echo = $redis->rpop($my_key);
//it returns false if the key doesn't exist, but i've shown that it clearly exists so why is it returning false???
if ($my_echo == false) {
print $my_key;
//print '5'.$key;
//print "5failure";
}
else
{
print $my_echo;
}
?>
当我弹出“my_control”时,我从一个客户端获取{“key”:“\nubuntureft22”},然后使用浏览器从另一个客户端获取ubunturight22。当我从命令行手动弹出时,我得到以下信息:
redis-cli
127.0.0.1:6379> rpop my_control
"ubunturight22"
127.0.0.1:6379> rpop my_control
"{ \"key\": \"\\nubuntuleft23\" }"
127.0.0.1:6379> rpop "my_control"
"ubunturight23"
127.0.0.1:6379
尝试var_dump($my_echo)并检查键是否正确?我在$my_echo和$my_键上使用了var_dump,结果是:bool(false)字符串(13)“ubunturight20”,这正是我所期望的。除了双引号,但我猜这一定是var_dump()的函数?试试var_dump($redis->keys(“*”);在rpop之前,如果密钥是exits或notYes,则在按照指示执行操作时,我的密钥似乎不可见。
redis-cli
127.0.0.1:6379> rpop my_control
"ubunturight22"
127.0.0.1:6379> rpop my_control
"{ \"key\": \"\\nubuntuleft23\" }"
127.0.0.1:6379> rpop "my_control"
"ubunturight23"
127.0.0.1:6379