如何使用php$\u post对两个结果求和

我想求结果1和结果2的和 我该怎么做请帮我解决这个问题

谢谢

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例如： $res+res1 =最终结果

这是结果1代码

<?php //Starting of php 
    if(isset($_POST['submit']))//if the submit button has pressed
    {
    $first = $_POST['first']; //Getting Value of first integer from add.html
    $sec = $_POST['sec']; //Getting Value of Second integer from add.html
    $res = $first * $sec *75 /365 /30; //Adding the two values and placing the added result to 'res' variable
    echo 'Added Result:';

    echo number_format((round($res, 1)),3);


    }
    //Ending of php
    ?>

这是第二个结果代码

<?php //Starting of php 
if(isset($_POST['submit']))//if the submit button has pressed
{
$days1 = $_POST['days1']; //Getting Value of first integer from add.html
$year1 = $_POST['year1']; //Getting Value of Second integer from add.html
$res1 = $days1 * $year1 *75 /365 /30; //Adding the two values and placing the added result to 'res' variable
echo 'Added Result:';

echo number_format((round($res1, 1)),3);


}
//Ending of php
?>

试试这个

<?php //Starting of php 
    if(isset($_POST['submit']))//if the submit button has pressed
    {
    $first = $_POST['first']; //Getting Value of first integer from add.html
    $sec = $_POST['sec']; //Getting Value of Second integer from add.html
    $days1 = $_POST['days1']; //Getting Value of first integer from add.html
    $year1 = $_POST['year1']; //Getting Value of Second integer from add.html
    $res1 = $days1 * $year1 *75 /365 /30; //Adding the two values and placing the added result to 'res' variable    
    $res = $first * $sec *75 /365 /30; //Adding the two values and placing the added result to 'res' variable
    $result1  = number_format((round($res1, 1)),3);
        echo 'Added Result:';

    $result2 = number_format((round($res, 1)),3);
    echo $final_result   = number_format(($result1 +$result2),3);

    }
    //Ending of php
    ?>

试试这个

<?php //Starting of php 
    if(isset($_POST['submit']))//if the submit button has pressed
    {
    $first = $_POST['first']; //Getting Value of first integer from add.html
    $sec = $_POST['sec']; //Getting Value of Second integer from add.html
    $days1 = $_POST['days1']; //Getting Value of first integer from add.html
    $year1 = $_POST['year1']; //Getting Value of Second integer from add.html
    $res1 = $days1 * $year1 *75 /365 /30; //Adding the two values and placing the added result to 'res' variable    
    $res = $first * $sec *75 /365 /30; //Adding the two values and placing the added result to 'res' variable
    $result1  = number_format((round($res1, 1)),3);
        echo 'Added Result:';

    $result2 = number_format((round($res, 1)),3);
    echo $final_result   = number_format(($result1 +$result2),3);

    }
    //Ending of php
    ?>

你说的是求和，你做的是$first*$sec*75/365/30，所以问题不清楚这些在同一页或不同的文件上？为什么乘法被描述为“加法”？那么你问的答案有什么问题，并接受了20分钟。ago？亲爱的@Fred ii-这是不同的问题，这就是为什么我问你说的是sum，你做的是$first*$sec*75/365/30，所以问题不清楚，这些是在同一页还是不同的文件上？为什么乘法被描述为“加法”？那么你问的答案有什么问题，并且接受了20分钟。前？亲爱的@Fred ii-这是不同的问题，这就是为什么我问zeeshan你能给我你的fb电子邮件id吗？你可以在我的个人资料上看到，如果这个答案有助于你接受。zeeshan你能给我你的fb电子邮件id吗？你可以在我的个人资料上看到，如果这个答案有助于你接受。