Php 元素被洗牌时的数组映射
我有这个数组(它只是其中的一部分)。6=问题ID,选项ID=可能的答案Php 元素被洗牌时的数组映射,php,shuffle,array-map,Php,Shuffle,Array Map,我有这个数组(它只是其中的一部分)。6=问题ID,选项ID=可能的答案 Array ( [3] => Array ( [0] => 6 [1] => Array ( [0] => Array ( [optionID] => 16
Array
(
[3] => Array
(
[0] => 6
[1] => Array
(
[0] => Array
(
[optionID] => 16
[isCorrect] => 0
)
[1] => Array
(
[optionID] => 14
[isCorrect] => 1
)
[2] => Array
(
[optionID] => 15
[isCorrect] => 0
)
[3] => Array
(
[optionID] => 17
[isCorrect] => 0
)
)
)
[7] => Array
(
[0] => 6
[1] => Array
(
[0] => Array
(
[optionID] => 16
[isCorrect] => 0
)
[1] => Array
(
[optionID] => 15
[isCorrect] => 0
)
[2] => Array
(
[optionID] => 17
[isCorrect] => 0
)
[3] => Array
(
[optionID] => 14
[isCorrect] => 1
)
)
)
)
我正在尝试将冗余问题(6和6)与数组_映射合并:
$unique = array_map('unserialize', array_unique(array_map('serialize', $quizQuestionArray)));
只要optionID的顺序相同,它就可以工作。但在某些情况下(比如这里),它们被洗牌(16,14,15,17)(16,15,17,14)。有没有办法让它们乱序并删除重复的问题?在应用array\u map()函数之前,您需要将它们按相同的顺序排序。您可以使用该函数并提供自己的比较函数,如下所示:
// Example array
$array = array(
3 => array(
0 => 6,
1 => array(
0 => array(
'optionID' => 16,
'isCorrect' => 0
),
1 => array(
'optionID' => 14,
'isCorrect' => 1
),
2 => array(
'optionID' => 15,
'isCorrect' => 0
),
3 => array(
'optionID' => 17,
'isCorrect' => 0
),
)
),
7 => array(
0 => 6,
1 => array(
0 => array(
'optionID' => 16,
'isCorrect' => 0
),
1 => array(
'optionID' => 15,
'isCorrect' => 0
),
2 => array(
'optionID' => 17,
'isCorrect' => 0
),
3 => array(
'optionID' => 14,
'isCorrect' => 1
),
)
)
);
// You can supply parts of an array to uasort()
// uasort() will modify your array but keep your keys.
uasort($array[3][2], 'sort_by_optionid');
uasort($array[7][3], 'sort_by_optionid');
function sort_by_optionid($a, $b) {
if ($a['optionID'] === $b['optionID']) {
return 0;
} else if ($a['optionID'] > $b['optionID']) {
return 1;
} else {
return -1;
}
}
// Done.
现在保留了键,您可以轻松地排列_map()以查找重复项,然后根据键再次排序回原始状态。例如,使用阵列(map-serialize是一种非常粗糙的阵列重复数据消除方法。您应该使用类似以下内容:
$dupeIds = [];
$array = array_filter($array, function ($item) use (&$dupeIds) {
$keep = !isset($dupeIds[$item[0]]);
$dupeIds[$item[0]] = true;
return $keep;
});
这是一个非常聪明的解决方案+1+1. 当然,它会返回那些应该消失的,以获得其余的:$remove=!isset($dupeIds[$item[0]])@用户3385195对,修复了那个bug。