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使用php获取要显示的html表单输入字段_Php_Html - Fatal编程技术网

使用php获取要显示的html表单输入字段

使用php获取要显示的html表单输入字段,php,html,Php,Html,我希望我的输入字段与echo语句一起显示。我收到了以下错误“解析错误:语法错误,意外的T_常量_封装的_字符串,在第8行的/home/content/76/12797276/html/stu05/homety one/student.php中应为“,”或“;” 你知道发生了什么事吗? 这是我的密码 <form action = student.php method="get"> First name: <input type=text name=fname><br&

我希望我的输入字段与echo语句一起显示。我收到了以下错误“解析错误:语法错误,意外的T_常量_封装的_字符串,在第8行的/home/content/76/12797276/html/stu05/homety one/student.php中应为“,”或“;”

你知道发生了什么事吗? 这是我的密码

<form action = student.php method="get">
First name:
<input type=text name=fname><br><br>
Last name:
<input type=text name=lname><br><br>
Student ID:
<input type=text name=studentid><br><br>

Gender: 
<select name="gender">
<option  value="male">Male</option>
<option  value="female">Female</option>
</select><br><br>

Semester: 
<select name="semester">
<option  value="winter">Winter</option>
<option  value="spring">Spring</option>
<option  value="summer">Summer</option>
<option  value="fall">Fall</option>


</select><br><br>
<input type=submit value="Click">

</form>

名字:


姓氏:

学生证:

性别: 男性 女性

学期: 冬天 春天 夏天 落下

还有php代码

<?
$name_first = $_GET['fname'];
$name_last = $_GET['lname'];
$student_ID = $_GET['studentid'];
$gender_select = $_GET['gender'];
$semester_select = $_GET['semester'];

echo "User ".$name_first" ".$name_last<br>
"Student ID: ".$student_ID<br>
"is a ".$gender_select " and has enrolled in the ".$semester_select "semester    ";

?>

这是无效的:

echo "User ".$name_first" ".$name_last<br>
echo“User”。$name\u第一个“$name\u最后一个”
这样说:

echo "User ".$name_first." ".$name_last."<br>
echo“User”。$name\u优先。“$name\u最后。”
您忘记了连接。您的最终代码应该是:

echo "User ".$name_first." ".$name_last."<br>Student ID: ".$student_ID."<br>is a ".$gender_select." and has enrolled in the ".$semester_select."semester    ";
echo“User”。$name\u first.“$name\u last.”
学生ID:“..$Student\u ID.”
是一个“$gender\u select.”并且已经注册了“$sembert\u select.”学期;

每一个代码,您都留下了第二个

非常感谢。问题解决了!