使用PHP MySQLi数据库类进行SQL查询

我使用的是PHP MySQLi数据库类MysqliDb.PHP

我有这个疑问，但是Wamp说：

致命错误：准备查询时出现问题

 SELECT car_id FROM gm_cars WHERE car_id NOT IN 
( 
  SELECT reserve_car_id FROM gm_reservations 
 WHERE reserve_dropOff > ? AND reserve_dropOff = ? AND reserve_pickUp ) 

年的联合税收协定1 C:\wamp\www\work\libs\PHP MySQLi数据库类master\MysqliDb.PHP，第823行

查询： 连接到数据库

>$carsBetweenDates = $db->rawQuery
('SELECT car_id FROM gm_cars WHERE car_id NOT IN 
   (SELECT reserve_car_id FROM gm_reservations 
     WHERE reserve_dropOff > ? AND reserve_dropOff <= ? 
     UNION 
     DISTINCT SELECT reserve_car_id FROM gm_reservations 
      WHERE reserve_pickUp >= ? AND reserve_pickUp < ?)', 
      Array('2014-12-20 20:00:00', '2014-12-22 20:00:00', 
      '2014-12-20 20:00:00', '2014-12-22 20:00:00'));

---

我看不出有什么错误。非常感谢。对不起，我说的是英语。

你能试着像这样调用函数吗：

$db->rawQuery('QUERY', array(), FALSE);

我认为清理会破坏您的查询，它可能会删除html字符，在您的情况下是<>条件

假设这是一个类：

---

尝试更改查询以简化查询。首先，将两个表合并为一个表，然后反转条件以部分删除NOT IN

SELECT gm_cars.car_id 
FROM gm_cars LEFT JOIN gm_reservations
ON gm_cars.car_id = gm_reservations.reserve_car_id
WHERE (reserve_dropOff <= ? OR reserve_dropOff > ?)
    AND (reserve_pickUp < ? OR reserve_pickUp >= ?)
    AND gm_cars.car_id NOT IN Array('...')
GROUP BY gm_cars.car_id

举个例子

$db->rawQuery("SELECT * FROM print_orders WHERE print_guests.id = print_orders.id AND print_order_products.order_id = print_orders.id AND  print_orders.id = ? AND print_guests.email = ?  AND print_order_products.order_id = ? " , array($_POST['orden'], $_POST['email'], $_POST['orden']));

$db->rawQuery("SELECT * FROM print_orders WHERE print_guests.id = print_orders.id AND print_order_products.order_id = print_orders.id AND  print_orders.id = ? AND print_guests.email = ?  AND print_order_products.order_id = ? " , array($_POST['orden'], $_POST['email'], $_POST['orden']));