Php 使用正则表达式提取内容

我有以下句子：enum'active'、'disabled'、'deleted'。我想要的是一个包含以下内容的阵列：

array(
    [0]=>'active',
    [1]=>'disabled',
    [2]=>'deleted'
)

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如何实现这一点？

在给定字符串的情况下，类似于此正则表达式的东西应该可以工作

$sentence = "enum('active','disabled','deleted')";
preg_match_all("/'([^']*)'/", $sentence, $matches);
print_r($matches[1]);

上述代码输出以下内容

Array
(
    [0] => active
    [1] => disabled
    [2] => deleted
)

Regex解释道

'               //Match opening quote.
    (           //Start capture.
        [^']*   //Match any characters but the end quote.
    )           //End capture.
'               //Match closing quote.

(               //Start capture.
    '           //Match opening quote.
        [^']*   //Match any characters but the end quote.
    '           //Match closing quote.
)               //End capture.

更新：

一位评论员建议，也许你希望保留这些引文。如果是这样，下面的正则表达式将起作用

$s = "enum('active','disabled','deleted')";
preg_match_all("/('[^']*')/", $s, $matches);
print_r($matches[1]);

输出

Array
(
    [0] => 'active'
    [1] => 'disabled'
    [2] => 'deleted'
)

Regex解释道

'               //Match opening quote.
    (           //Start capture.
        [^']*   //Match any characters but the end quote.
    )           //End capture.
'               //Match closing quote.

(               //Start capture.
    '           //Match opening quote.
        [^']*   //Match any characters but the end quote.
    '           //Match closing quote.
)               //End capture.

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您可以使用此正则表达式：

'(\w+?)'

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比赛结果中是否应该包括报价？