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Php html dom在结果存在时不会给出结果_Php_Curl_Simple Html Dom - Fatal编程技术网

Php html dom在结果存在时不会给出结果

Php html dom在结果存在时不会给出结果,php,curl,simple-html-dom,Php,Curl,Simple Html Dom,我正在尝试获取网页的标题,请参见下面的代码 include("simple_html_dom.php"); $url = "http://fzmoviez.in/video/list/4059539"; $base = $url; $curl = curl_init(); curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt($curl, CURLOPT_HEADER, false); curl_setopt($curl

我正在尝试获取网页的标题,请参见下面的代码

include("simple_html_dom.php");
$url = "http://fzmoviez.in/video/list/4059539";

$base = $url;

$curl = curl_init();
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, FALSE);
curl_setopt($curl, CURLOPT_HEADER, false);
curl_setopt($curl, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($curl, CURLOPT_URL, $base);
curl_setopt($curl, CURLOPT_REFERER, $base);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, TRUE);
$str = curl_exec($curl);
curl_close($curl);

// Create a DOM object
$html_base = new simple_html_dom();
// Load HTML from a string
$html_base->load($str);
$title = $html_base->getElementsByTagName("title")->innertext; //line 21
echo $title;
我得到一个错误:

Notice: Trying to get property of non-object in C:\xampp\htdocs\... on line 21
但是当我
var\u dump($html\u base)

object(simple_html_dom)#1 (23) { ["root"]=> object(simple...
    ... card" ["attr"]=> array(2) { ["id"]=> string(5) "index" ["title"]=> string(179) "FzMoviez.iN - Free Download Latest Bollywood Movies,Hindi Dudded Movies,Hollywood Movies,Live Movies,WWE Shows,Mp4,HD Mp4,High Quality Mp4,Avi,Iphone,Android,Tablets And Many More" } ["children"]=> array(25) { [0]=> object(simple_html_dom_node)#55 (9) { ["nodetype"]=>......
意思是,它是一个对象并且有标题,为什么要给出错误

Notice: Trying to get property of non-object in C:\xampp\htdocs\.. on line 21

$html\u base->getElementsByTagName(“title”)


将返回元素数组,您需要迭代此数组以获取数据。

很难说,因为您已删除了大部分转储,但看起来
title
是一个属性,而不是标记名。