Php 基于PDF格式的XSL 建议uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

嘿，伙计们。。我在做一个项目，遇到了这个小问题。。每当“”中的“student_name”有值时，它都会显示：

输出：建议John DOE将收到 以下服务/安置

我怎样才能想出一个解决方案，只要“学生名”不是 设置后，它将只显示“建议\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu 将接受以下服务/安置。”？帮帮我。

看看

将接受以下服务/安置：

这不是一个有效的例子，但我希望它能让你知道在哪里可以看到

首先，请看一下文档。阅读所有文档不超过15-20分钟

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您可以简单地使用xsl:if语句，它允许您测试节点是否在那里，就像您在使用xsl:choose时所做的那样，但是您可能可以在这样一行中实现您想要的结果

<fo:block>
<xsl:choose>
  <xsl:when test="/root/demo/student_name != ''">
     <xsl:value-of select="/root/demo/student_name"/>
  </xsl:when>
  <xsl:otherwise>
    <fo:inline text-decoration="underline">   </fo:inline> 
  </xsl:otherwise>
</xsl:choose>
will receive the following services/placement: 
</fo:block>

建议uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

这将检查是否存在student_name节点，如果要检查该节点是否为空，则可以使用！=比较器，但在这种情况下它似乎没有必要，因为如果它是空的，如果您不以任何主要方式更改间距或位置，它应该不会造成任何影响

<fo:block>
<xsl:choose>
  <xsl:when test="/root/demo/student_name != ''">
     <xsl:value-of select="/root/demo/student_name"/>
  </xsl:when>
  <xsl:otherwise>
    <fo:inline text-decoration="underline">   </fo:inline> 
  </xsl:otherwise>
</xsl:choose>
will receive the following services/placement: 
</fo:block>

<fo:block>

It has been recommended that _______________<xsl:if test="/root/demo/student_name"><fo:inline text-decoration="underline"><xsl:value-of select="/root/demo/student_name"/></fo:inline></xsl:if> will receive the following services/placement:      

</fo:block>