在PHP中检查较大字符串中的JSON字符串

以下是日志文件条目的示例：

[22-Aug-2017 16:19:58 America/New_York] WP_Community_Events::maybe_log_events_response: Valid response received. Details: {"api_url":"https:\/\/api.wordpress.org\/events\/1.0\/","request_args":{"body":{"number":5,"ip":"192.168.99.0","locale":"en_GB","timezone":"America\/New_York"}},"response_code":200,"response_body":{"location":{"ip":"47.197.97.47"},"events":"5 events trimmed."}}

---

{“api\u url”：“https:\/\/api.wordpress….

部分是有效的JSON，但显然是整个字符串本身（日志条目行）不是。我遇到了一个难题，可以在不弄乱字符串任何其他部分的情况下基本上拉出JSON。

只需删除前面字符串中的所有内容，并包括给定的子字符串“Details:”：

---

您可以尝试获取json对象的开头和结尾并对其进行解码。若并没有json解码错误，那个么您就可以了。这假设字符

{

和

}

仅在json正文中使用

function checkIfStringHasValidJson($string)
{
    $start = strpos($string, '{');
    $end = strrpos($string, '}');
    $json = substr($string, $start, $end);
    json_decode($json);
    return json_last_error() === JSON_ERROR_NONE;
}

用于查找所有JSON并将其存储到如下数组中：

$text = '[22-Aug-2017 16:19:58 America/New_York] WP_Community_Events::maybe_log_events_response: Valid response received. Details: {"api_url":"https:\/\/api.wordpress.org\/events\/1.0\/","request_args":{"body":{"number":5,"ip":"192.168.99.0","locale":"en_GB","timezone":"America\/New_York"}},"response_code":200,"response_body":{"location":{"ip":"47.197.97.47"},"events":"5 events trimmed."}}';

preg_match_all('/\{(?:[^{}]|(?R))*\}/x', $text, $matches);

echo '<pre>';
print_r($matches[0]);

您可以从以下网站了解更多信息：

或者，如果您想要相反的结果并删除JSON并保留字符串，则可以使用：

[22-Aug-2017 16:19:58 America/New_York] WP_Community_Events::maybe_log_events_response: Valid response received. Details:

归功于

这将产生：

$text = '[22-Aug-2017 16:19:58 America/New_York] WP_Community_Events::maybe_log_events_response: Valid response received. Details: {"api_url":"https:\/\/api.wordpress.org\/events\/1.0\/","request_args":{"body":{"number":5,"ip":"192.168.99.0","locale":"en_GB","timezone":"America\/New_York"}},"response_code":200,"response_body":{"location":{"ip":"47.197.97.47"},"events":"5 events trimmed."}}';

$cleantext = preg_replace('~\{(?:[^{}]|(?R))*\}~', '', $text);

echo $cleantext;

---

看起来你可以在第一个大括号之前剪切所有内容，在最后一个大括号之后剪切所有内容。我想JSON是在

细节之后：

我想。这是一个提示。这是一个例子。它并不总是在前面有“细节”（或其他相关内容），它想说这也行得通，但preg_match_all会得到所有细节（如果不止一个存在）@Norcross是有道理的，我假设只有一个物体，并且故意让它保持光亮。很高兴你有了一个解决方案！

$text = '[22-Aug-2017 16:19:58 America/New_York] WP_Community_Events::maybe_log_events_response: Valid response received. Details: {"api_url":"https:\/\/api.wordpress.org\/events\/1.0\/","request_args":{"body":{"number":5,"ip":"192.168.99.0","locale":"en_GB","timezone":"America\/New_York"}},"response_code":200,"response_body":{"location":{"ip":"47.197.97.47"},"events":"5 events trimmed."}}';

$cleantext = preg_replace('~\{(?:[^{}]|(?R))*\}~', '', $text);

echo $cleantext;

[22-Aug-2017 16:19:58 America/New_York] WP_Community_Events::maybe_log_events_response: Valid response received. Details: