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Php JSON解码卷曲问题_Php_Json - Fatal编程技术网

Php JSON解码卷曲问题

Php JSON解码卷曲问题,php,json,Php,Json,嗨,我正试图使用这个url从wikipedia调用这个api,但是当我转储变量时它说它是空的。此函数适用于我的其他json api调用,但不适用于此,我在broswer中手动测试了它,它给出了一个结果。这是我的尝试 $url = 'http://en.wikipedia.org/w/api.php?action=query&format=json&titles=Image:Romerolagus diazi (dispale) 001.jpg&prop=imageinfo

嗨,我正试图使用这个url从wikipedia调用这个api,但是当我转储变量时它说它是空的。此函数适用于我的其他json api调用,但不适用于此,我在broswer中手动测试了它,它给出了一个结果。这是我的尝试

$url = 'http://en.wikipedia.org/w/api.php?action=query&format=json&titles=Image:Romerolagus diazi (dispale) 001.jpg&prop=imageinfo&iiprop=url'; 

 $result = apicall($url);
 var_dump($result);     

 function apicall($url){

  $ch = curl_init();
  curl_setopt($ch, CURLOPT_URL, $url);
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
  curl_setopt($ch, CURLOPT_USERAGENT, 'MyBot/1.0 (http://www.mysite.com/)');

  $result = curl_exec($ch);

  if (!$result) {
    exit('cURL Error: '.curl_error($ch));
  }

  $var = json_decode($result);


  return $var;

}
urlencode()
问题,如下修改

    <?php
$url = 'http://en.wikipedia.org/w/api.php'; 
$titles = urlencode('Image:Romerolagus diazi (dispale) 001.jpg');
$queryStr = 'action=query&format=json&titles='.$titles.'&prop=imageinfo&iiprop=url';
$url = $url . '?' . $queryStr;

 $result = apicall($url);
 var_dump($result);     

 function apicall($url){

  $ch = curl_init();
  curl_setopt($ch, CURLOPT_URL, $url);
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
  curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.22 (KHTML, like Gecko) Chrome/25.0.1364.172 Safari/537.22');

  $result = curl_exec($ch);

  if (!$result) {
    exit('cURL Error: '.curl_error($ch));
  }

  var_dump($result);
  $var = json_decode($result);


  return $var;

}
<代码> 您应该考虑使用URL:

$url = 'http://en.wikipedia.org/w/api.php?' . http_build_query(array(
    'action' => 'query',
    'format' => 'json',
    'titles' => 'Image:Romerolagus diazi (dispale) 001.jpg',
    'prop' => 'imageinfo',
    'iiprop' =>  'url',
));
“不工作”是什么意思?它会输出“我不工作”还是什么?