Php iOS-目标C-POST字符串转义/编码问题

经过大约一周的研究，没有解决方案，我放弃了，我向你们寻求建议

我需要相同的php脚本以相同的方式处理POST请求，而不管它们的来源是简单的HTML表单还是iOS应用程序。不涉及JSON

问题：当POST发件人是iOS应用程序时，某些字符丢失。在这一点上，我想说，我不知道为什么它会这样。显然，web浏览器在POST请求的构建过程中正确地逃逸了所有字符，而我的obj-c代码却没有

在objective-c代码中，您可以看到我所做的5个Tentive，并注意到出错的地方

我真的希望你能帮忙

tester.php文件：

<?php
header('Content-Type: text/html; charset=utf-8');

if (isset($_POST['email']))
{
    echo "email: " . $_POST['email'];
    echo "\n";
    echo "password: " . $_POST['password'];
}
else
{
?>

<form method="post">
    <input type="text" id="email" name="email" value="切换到中文@gmail.com" />
    <br>
    <input type="text" id="password" name="password" value="&+=/切/().%&" />
    <br>
    <input type="submit" />

</form>

<?php
}

如果我使用HTML表单（与我在表单中输入的内容完全相同），则返回结果：

我从objective c代码（一些字符消失）中得到的，这是最后的测试之一：

2016-09-29 21:28:59.519 test[44752:2438179] Before: 切换到中文@gmail.com (15) and &+=/切/().%& (11)
2016-09-29 21:28:59.705 test[44752:2438721] email: 切换到中文@gmail.com password: &+=/切/().&

---

我就是这样做的。我试过的每件事都很管用。首先，您需要将该函数添加到NSString：

@implementation NSString (NSStringWebStructure)
-(NSString*)stringToWebStructure
{
    NSString* webString = [self stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

    webString = [webString stringByReplacingOccurrencesOfString:@"&" withString:@"%26"];
    webString = [webString stringByReplacingOccurrencesOfString:@"?" withString:@"%3F"];

    return webString;
}
@end

现在您需要请求函数：

-(NSString*)launchURL:(NSURL*)url withPostString:(NSString*)post
{
    NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
    NSString *postLength = [NSString stringWithFormat:@"%lu", (unsigned long)[postData length]];

    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
    [request setURL:url];
    [request setHTTPMethod:@"POST"];
    [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
    [request setHTTPBody:postData];

    NSError *error = nil;
    NSHTTPURLResponse *response = nil;
    NSData *urlData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];

    if (response.statusCode >= 200 && response.statusCode < 300)
    {
        NSString *responseData = [[NSString alloc] initWithData:urlData encoding:NSUTF8StringEncoding];
        if (responseData.length > 0) return responseData;
    }
    else if (error) return [error description];

    return nil;
}
-(NSString*)launchURL:(NSURL*)url withPostValues:(NSDictionary*)postDict
{
    NSArray* postKeys = postDict.allKeys;
    NSMutableArray* postLines = [[NSMutableArray alloc] init];

    for (NSString* key in postKeys)
    {
        [postLines addObject:[NSString stringWithFormat:@"%@=%@",key,[postDict[key] stringToWebStructure]]];
    }

    return [self launchURL:url withPostString:[postLines componentsJoinedByString:@"&"]];
}

---

stringByAddingPercentEscapesUsingEncoding:

在macOS 10.11中被弃用，但如果您打算像我一样支持旧的macOS版本，这是一种功能性方法（从macOS 10.6到macOS 10.12进行测试）。

这是我的做法。我试过的每件事都很管用。首先，您需要将该函数添加到NSString：

@implementation NSString (NSStringWebStructure)
-(NSString*)stringToWebStructure
{
    NSString* webString = [self stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

    webString = [webString stringByReplacingOccurrencesOfString:@"&" withString:@"%26"];
    webString = [webString stringByReplacingOccurrencesOfString:@"?" withString:@"%3F"];

    return webString;
}
@end

现在您需要请求函数：

-(NSString*)launchURL:(NSURL*)url withPostString:(NSString*)post
{
    NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
    NSString *postLength = [NSString stringWithFormat:@"%lu", (unsigned long)[postData length]];

    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
    [request setURL:url];
    [request setHTTPMethod:@"POST"];
    [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
    [request setHTTPBody:postData];

    NSError *error = nil;
    NSHTTPURLResponse *response = nil;
    NSData *urlData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];

    if (response.statusCode >= 200 && response.statusCode < 300)
    {
        NSString *responseData = [[NSString alloc] initWithData:urlData encoding:NSUTF8StringEncoding];
        if (responseData.length > 0) return responseData;
    }
    else if (error) return [error description];

    return nil;
}
-(NSString*)launchURL:(NSURL*)url withPostValues:(NSDictionary*)postDict
{
    NSArray* postKeys = postDict.allKeys;
    NSMutableArray* postLines = [[NSMutableArray alloc] init];

    for (NSString* key in postKeys)
    {
        [postLines addObject:[NSString stringWithFormat:@"%@=%@",key,[postDict[key] stringToWebStructure]]];
    }

    return [self launchURL:url withPostString:[postLines componentsJoinedByString:@"&"]];
}

stringbyaddingpercentescapesusingencode:

在macOS 10.11中被弃用，但如果您打算像我一样支持旧的macOS版本，这是一种功能性方法（从macOS 10.6到macOS 10.12进行测试）

NSString *email    = @"切换到中文@gmail.com";
NSString *password = @"&+=/切/().%&";

NSURL *url = [NSURL URLWithString:@"http://localhost:8080/tester.php"];
NSDictionary* postValues = @{@"email":email, @"password": password};

NSString* response = [self launchURL:url withPostValues: postValues];
NSLog(@"%@",response);