XML，使用PHP创建文件_Php_Xml

XML，使用PHP创建文件

php xml

XML，使用PHP创建文件,php,xml,Php,Xml,我有一个SQL数据库，正在对其执行以下查询 $statistics="SELECT firstname AS 'user', count( * ) AS 'num',member_id AS ID FROM members JOIN member_photo USING ( member_id ) GROUP BY firstname "; $result= mysql_query($statisti

我有一个SQL数据库，正在对其执行以下查询

        $statistics="SELECT firstname AS 'user', count( * ) AS 'num',member_id AS ID
        FROM members
        JOIN member_photo
        USING ( member_id )
        GROUP BY firstname ";
        $result= mysql_query($statistics);

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

这将检索上传者以及他们以以下格式上传的照片数量

        Uploader  Number of photos uploaded
          mun             20
          ris             10
          moz              5

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

我想要的是一个PHP脚本来创建XML文件。它必须实际保存在我的目录中。我使用SimpleXML来实现这一点

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

我就是这么做的

    $xmlDoc=loadXMLDoc("photo.xml");

        $statistics="SELECT firstname AS 'user', count( * ) AS 'num',member_id AS ID
        FROM members
        JOIN member_photo
        USING ( member_id )
        GROUP BY firstname ";
        $result= mysql_query($statistics);


    while($row=mysql_fetch_assoc($result)) {

    $uploader=$xml->addChild('uploader');
    $uploader->addAttribute('ID',$row['ID']);
    $uploader->addChild('Name', $row['user']);
    $uploader->addChild('Photos_Uploaded', $row['num']);
    $xml->asXML('photo.xml');

    }

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

其中photo.xml是保存xml节点的文件。它们是这种格式的

      <?xml version="1.0"?>

      <?xml-stylesheet type="text/xsl" href="user.xsl"?>


      <users xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="users.xsd">




       <uploader ID="11"><Name>moz</Name><Photos_Uploaded>2</Photos_Uploaded>             </uploader>

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

      </users>

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>


moz2
Mun6
风险10

现在假设用户“Moz”上传了一张新照片。他的照片计数器最初是2，应该改为3。XML文件应该反映这种更改，对吗？这是因为它从数据库中提取数据（还记得查询吗？），但问题出在这里

      <uploader ID="11"><Name>moz</Name><Photos_Uploaded>2</Photos_Uploaded>             </uploader>

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

moz2
Mun6
风险10

moz3

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

Mun6
风险10

它还复制了其他节点，从而将复制创建到XML文件中

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

我想到的是

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

在再次填充XML文件之前，首先清除该文件

有人知道怎么做吗？使用php或javascript？

那么您是在询问如何在编写/重写photo.xml文件之前“清空”它？对吗

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

我不熟悉SimpleXML，所以我不知道是否有一个标志可以用于它，但您可以始终使用：

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

$f = fopen("photo.xml", "w");
fclose($f);

这将：“仅为写入而打开；将文件指针放在文件开头，并将文件截断为零长度。如果文件不存在，请尝试创建它。”

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

（见：）

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

编辑

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

仔细查看SimpleXML之后，您可能希望有两个文件，一个是要加载的xml文档模板，另一个是要保存的文件（photo.xml）。使用带有“w”标志的fopen将清除内容，但也会丢失xml结构

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

所以实际上，你可能根本不需要使用fopen

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

$xmlDoc=loadXMLDoc("photo_template.xml");

        $statistics="SELECT firstname AS 'user', count( * ) AS 'num',member_id AS ID
        FROM members
        JOIN member_photo
        USING ( member_id )
        GROUP BY firstname ";
        $result= mysql_query($statistics);


    while($row=mysql_fetch_assoc($result)) {

    $uploader=$xml->addChild('uploader');
    $uploader->addAttribute('ID',$row['ID']);
    $uploader->addChild('Name', $row['user']);
    $uploader->addChild('Photos_Uploaded', $row['num']);
    $xml->asXML('photo.xml');

    }

其中photo_template.xml看起来像：

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="user.xsl"?>
    <users xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="users.xsd">
    </users>

而photo.xml最终将看起来像：

       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>

      <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>

<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="user.xsl"?>
    <users xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="users.xsd">
       <uploader ID="11"><Name>moz</Name><Photos_Uploaded>2</Photos_Uploaded>             </uploader>
       <uploader ID="13"><Name>Mun</Name><Photos_Uploaded>6</Photos_Uploaded></uploader>
       <uploader ID="12"><Name>ris</Name><Photos_Uploaded>10</Photos_Uploaded></uploader>
    </users>


moz2
Mun6
风险10

+1为了向其他人展示足够的示例代码以理解您的问题，您总是从数据库中获取要写入文件的完整数据集？是的，总是因为删除内容并再次写入整个新内容更容易、更简单+1表示打开标志“w”。这可能比有选择地附加新条目的xml节点条件化检查更有意义。但是打开标志“w”会删除我不想删除的xml结构。谢谢mason81。你是个救生员！