Php 表排除列的JSON数组
我编写了一个简单的函数,它获取我的一个数据库表并输出一个完整的JSON数组Php 表排除列的JSON数组,php,jquery,json,Php,Jquery,Json,我编写了一个简单的函数,它获取我的一个数据库表并输出一个完整的JSON数组 function tableJSON ($table, $orderby) { $array = array(); $sql = Nemesis::select("*", $table, NULL, $orderby); if ($sql) { if ($sql->num_rows > 0) { while ($row = $sql->fe
function tableJSON ($table, $orderby) {
$array = array();
$sql = Nemesis::select("*", $table, NULL, $orderby);
if ($sql) {
if ($sql->num_rows > 0) {
while ($row = $sql->fetch_assoc()) {
// push row values to array
array_push($array, $row);
}
return json_encode($array);
} else {
echo 'Query returned empty';
}
} else {
echo 'Query error';
}
}
从该数组中,使用所述方法生成一个表。然后我将表格分拣机应用于表格。我的问题是,目前,该脚本输出所有行和列。例如:
[{"id":"109225488","project_name":"One on One Interview the Dean of RSM","project_bold":"Interview","project_content":"Interview with the Dean of Erasmus University Rotterdam School of Management. Interviewer: Joost Kammermans.","project_image_1":"\/images\/uploads\/projects\/109225488\/m_109225488_1.jpg","project_image_2":"","project_image_3":"","project_image_4":"","youtube_link":"http:\/\/www.youtube.com\/watch?v=9rsR3FcLAxI","published":"1","created":"2013-05-29 14:07:49","created_by":"1","last_modified":"2013-07-22 19:43:15","last_modified_by":"1"}
如何从输出被排除列的数组中排除此脚本
例如:
$excluded=array('created_by','project_image_1')代码>
我尝试了array\u diff
,但没有成功
$sql = Nemesis::select("*", $table, NULL, $orderby);
将*
更改为只包含要输出的列的列表,这样您就不必担心后端阵列的麻烦。我建议Devisioner给出答案,但是
function tableJSON ($table, $orderby, $excluded = array()) {
$array = array();
$sql = Nemesis::select("*", $table, NULL, $orderby);
if ($sql) {
if ($sql->num_rows > 0) {
while ($row = $sql->fetch_assoc()) {
$newrow = array();
foreach($row as $col => $val)
if(!in_array($col, $excluded))
$newrow[$col] = $val;
// push row values to array
array_push($array, $newrow);
}
return json_encode($array);
} else {
echo 'Query returned empty';
}
} else {
echo 'Query error';
}
}
有趣的一点,但为了我自己的利益,我很好奇。在任何情况下,我都会投赞成票——只处理你需要的栏目是你最好的选择——你不必以奇怪的方式筛选数据。