Php 三值运算符中的PDO json_编码

我正在使用检查数据库中是否有用户信息

$usernameQuery->rowCount();

但是，我也将这段代码放在一个三元运算符中，并在json中回显结果，即“如果存在则为false，如果不存在则为true”，但它不起作用。我研究了一下，发现的信息没有帮助，也没有三元运算符。这是密码

PHP

---

试试这个，我想你没有检查条件

$count = $usernameQuery->rowCount();

$nullResult['Username'] = (!empty($count)) ? true: false;

在阅读了你的问题之后，有一件事也错了，你正在用不同的查询检查同一个表中的两列，我认为如果不需要按照你的要求分开的话，应该是这样的

$data = $handler->prepare( "SELECT * FROM app_signup WHERE email = ? OR username = ?");

$data>execute(array($email,$username));

然后检查

$nullResult = array();
$nullResult['Email'] = (!empty($data['email'])) ? $data['email'] : 'empty'; 
$nullResult['Username'] = (!empty($data->rowCount()) ? false : true;

这是一个基于您提供的详细信息的解决方案，希望对您有所帮助

<?php

if($_SERVER['REQUEST_METHOD'] =="POST"){

    $email = $_POST['email'];
    $username = $_POST['username'];

    //if email and username is empty then do this
    if(!empty($email) && !empty($username)){

        //Connect to database
        try{

        // new php data object
        $handler = new PDO('mysql:host=127.0.0.1;dbname=magicsever', 'root', '');
        //ATTR_ERRMODE set to exception
        $handler->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

    }catch(PDOException $e){
        die("There was an error connecting to the database");   

    }

        //find email and username and Prepare
        $dataQuery = $handler->prepare( "SELECT * FROM app_signup WHERE email = ? OR username = ?");

        //Execute;
        $dataQuery->execute(array($email,$user));

        $count = $dataQuery->rowCount()
        //Check if the email is empty
        if(!empty($count)){
                echo "Test";
        }else{

            $nullResult = array();
            $nullResult['Email'] = (!empty($data['email'])) ? $data['email'] : 'empty'; 
            $nullResult['Username'] = (!empty($data->rowCount()) ? false : true;
            echo json_encode($nullResult);
            die("");
        }

    }else{

        $nullResult = array();
        $nullResult['Email'] = (empty($data['email']))? "empty" : "";
        $nullResult['Username'] = (empty($data['username']))? "empty" : "";
        echo json_encode($nullResult);
        exit();

    }



}

---

我实际上通过改变一些东西来修复它。问题是if和else语句，我有“如果电子邮件和密码不是空的”，然后运行代码。但是我在if和else语句中检查用户名是否正确，电子邮件是否为空，因此第一部分变为false并运行按钮代码。这是密码

<?php

if($_SERVER['REQUEST_METHOD'] =="POST"){

    $email = $_POST['email'];
    $username = $_POST['username'];

    //if email and username is empty then do this
    if(empty($email) && empty($username)){
         $nullResult = array();
        $nullResult['Email'] = (empty($email))? "empty" : "";
        $nullResult['Username'] = (empty($username))? "empty" : "";
        echo json_encode($nullResult);
        exit();
    }

        //Connect to database
        try{

        // new php data object
        $handler = new PDO('mysql:host=127.0.0.1;dbname=magicsever', 'root', '');
        //ATTR_ERRMODE set to exception
        $handler->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

    }catch(PDOException $e){
        die("There was an error connecting to the database");   

    }

        //find email and username and Prepare
        $emailQuery = $handler->prepare( "SELECT * FROM app_signup WHERE email = ?");
        $usernameQuery = $handler->prepare("SELECT * FROM app_signup WHERE username = ?");

        //Execute;
        $emailQuery->execute(array($email));
        $usernameQuery->execute(array($username));

        //Check if the email is empty
        if(empty($email)){

            $nullResult = array();
            $nullResult['Email'] = (!empty($email))? "empty" : "";
            $nullResult['Username'] = ($usernameQuery->rowCount())? false: true;
            echo json_encode($nullResult);
            die("");

        }else{

            echo "Test";
        }



}





?>


我仍然得到一个空的“”空在哪里？在$nullResult['Username']？是的，它假设类似于{“Email”：“empty”，“Username”：“false”}我得到了一个错误并修复了我，现在我得到了这个错误解析错误：语法错误，意外“；”在第38行的C:\wamp64\www\MT\pdovalization.php中，我不确定为什么要添加（！empty（$data->rowCount（）），因为我正在检查用户信息是否在数据库中，而不是错误。
<?php

if($_SERVER['REQUEST_METHOD'] =="POST"){

    $email = $_POST['email'];
    $username = $_POST['username'];

    //if email and username is empty then do this
    if(empty($email) && empty($username)){
         $nullResult = array();
        $nullResult['Email'] = (empty($email))? "empty" : "";
        $nullResult['Username'] = (empty($username))? "empty" : "";
        echo json_encode($nullResult);
        exit();
    }

        //Connect to database
        try{

        // new php data object
        $handler = new PDO('mysql:host=127.0.0.1;dbname=magicsever', 'root', '');
        //ATTR_ERRMODE set to exception
        $handler->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

    }catch(PDOException $e){
        die("There was an error connecting to the database");   

    }

        //find email and username and Prepare
        $emailQuery = $handler->prepare( "SELECT * FROM app_signup WHERE email = ?");
        $usernameQuery = $handler->prepare("SELECT * FROM app_signup WHERE username = ?");

        //Execute;
        $emailQuery->execute(array($email));
        $usernameQuery->execute(array($username));

        //Check if the email is empty
        if(empty($email)){

            $nullResult = array();
            $nullResult['Email'] = (!empty($email))? "empty" : "";
            $nullResult['Username'] = ($usernameQuery->rowCount())? false: true;
            echo json_encode($nullResult);
            die("");

        }else{

            echo "Test";
        }



}





?>