如何使用ajax调用将post数据传递给php代码

我已经将html编写为

        <input type="button" onclick="saveAndSend()">

和用于保存数据的php代码

     public function saveAndSend()
     {
         // Send Logic

         // Save Logic
         $new_item = $this->apicaller->sendRequest(array(
            'controller' => 'Broadcast',
            'action' => 'save',
            'studentList' => $_POST['studentList'],
            'employeeList' => $_POST['employeeList'],
            'mailTitle' => $_POST['mailTitle'],
            'broadcastMessage' => $_POST['broadcastMessage'],
            'emailSent' => $_POST['emailSent']      
         ));

        echo $new_item; 
     }

---

我试图使用ajax调用将数据传递给php代码，这样页面就不会刷新，数据保存在MongoDB数据库中。上述代码不起作用。请帮忙

试试这段代码，它一定对你有帮助

<input type="button" onclick="saveAndSend()">
<script>
   // JS function  
    function saveAndSend()
    {
        var studentList = "1,2,3";
        var employeeList = "";
        var mailTitle = "Hello";
        var broadcastMessage = "How are you";
        var emailSent = "0";



        $.ajax({
            url: 'index.php?action=saveAndSend',
            type: 'POST',
            data: {'studentList': studentList, 'employeeList': employeeList, 'mailTitle': mailTitle, 'broadcastMessage': broadcastMessage, 'emailSent': emailSent},
            success: function () {
                alert("hello");

            },
            error: function () {
                alert('sorry');
            }
        });

    }
</script>

<?php
if($_GET['action'] = 'saveAndSend'){
    saveAndSend();
}
// PHP Function
function saveAndSend() {
    if (isset($_POST)) {
        echo '<pre>';
        print_r($_POST);
        echo '</pre>';
        die();
    }
}

//JS函数
函数saveAndSend（）
{
var studentList=“1,2,3”；
var employeeList=“”；
var mailttitle=“你好”；
var broadcastMessage=“你好”；
var emailSent=“0”；
$.ajax({
url:'index.php？action=saveAndSend'，
键入：“POST”，
数据：{'studentList'：studentList，'employeeList'：employeeList，'mailTitle'：mailTitle，'broadcastMessage'：broadcastMessage，'emailSent'：emailSent}，
成功：函数（）{
警惕（“你好”）；
},
错误：函数（）{
警惕（“对不起”）；
}
});
}
控制台中有错误吗？控制台中没有错误，但我认为它不会传递数据或运行php代码。请尝试设置contentType参数contentType不是必需的
var\u dump（$\u POST）来检查@Nida您正在ajax调用中添加TYPE=POST，并发送index.php？action=saveAndsend，这是作为GET类型的查询字符串url。
<input type="button" onclick="saveAndSend()">
<script>
   // JS function  
    function saveAndSend()
    {
        var studentList = "1,2,3";
        var employeeList = "";
        var mailTitle = "Hello";
        var broadcastMessage = "How are you";
        var emailSent = "0";



        $.ajax({
            url: 'index.php?action=saveAndSend',
            type: 'POST',
            data: {'studentList': studentList, 'employeeList': employeeList, 'mailTitle': mailTitle, 'broadcastMessage': broadcastMessage, 'emailSent': emailSent},
            success: function () {
                alert("hello");

            },
            error: function () {
                alert('sorry');
            }
        });

    }
</script>

<?php
if($_GET['action'] = 'saveAndSend'){
    saveAndSend();
}
// PHP Function
function saveAndSend() {
    if (isset($_POST)) {
        echo '<pre>';
        print_r($_POST);
        echo '</pre>';
        die();
    }
}