Php 按当前日期列出的SQL订单

我有一张这样的桌子，我想从当前的dayname开始订购

title   date_firstcall      totalViews  Tag
name A  2014-08-25 10:19:49     2   Monday
name B  2014-08-24 16:03:36     3   Sunday
name C  2014-08-24 14:54:47     2   Sunday
name C  2014-08-23 11:06:19     3   Saturday
name A  2014-08-23 00:05:35     16  Saturday
name B  2014-08-22 10:05:53     4   Friday
name A  2014-08-22 00:11:28     25  Friday
name C  2014-08-21 19:28:54     1   Thursday
name A  2014-08-21 08:44:05     13  Thursday
name C  2014-08-20 22:42:49     1   Wednesday
name D  2014-08-19 16:22:42     2   Tuesday
name A  2014-08-19 15:43:57     10  Tuesday
name B  2014-08-19 09:36:52     1   Tuesday

我的SQL语句不工作：

SELECT title as Seite, DAYNAME(CURRENT_DATE) AS diff,
 sum( if( Tag = 'Monday', totalViews, 0 ) ) AS Montag,
 sum( if( Tag = 'Wednesday', totalViews, 0 ) ) AS Mittwoch,
 sum( if( Tag = 'Tuesday', totalViews, 0 ) ) AS Dienstag,
 sum( if( Tag = 'Thursday', totalViews, 0 ) ) AS Donnerstag,
 sum( if( Tag = 'Friday', totalViews, 0 ) ) AS Freitag,
 sum( if( Tag = 'Saturday', totalViews, 0 ) ) AS Samstag,
 sum( if( Tag = 'Sunday', totalViews, 0 ) ) AS Sonntag
 FROM tmp  GROUP BY title ORDER BY diff

结果表首先从当天开始，然后是第二天。 比如：

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Thx可提前获取任何提示。

使用

工作日

获取星期几作为数字。减去当前日期的模7，使其环绕，然后旋转

SELECT title,
       SUM(IF(WEEKDAY(date_firstcall) = WEEKDAY(NOW()), totalViews, 0)) AS current_day,
       SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 1, totalViews, 0)) AS day_plus_1,
       SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 2, totalViews, 0)) AS day_plus_2,
       SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 3, totalViews, 0)) AS day_plus_3,
       SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 4, totalViews, 0)) AS day_plus_4,
       SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 5, totalViews, 0)) AS day_plus_5,
       SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 6, totalViews, 0)) AS day_plus_6
FROM tmp
GROUP BY title

以下是如何使用动态SQL获取日期名称：

SET @sql = (SELECT CONCAT('
     SELECT title,
            SUM(IF(WEEKDAY(date_firstcall) = WEEKDAY(NOW()), totalViews, 0)) AS ', DAYNAME(NOW()),
    ',      SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 1, totalViews, 0)) AS ', DAYNAME(DATE_ADD(NOW(), INTERVAL 1 DAY)),
    ',      SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 2, totalViews, 0)) AS ', DAYNAME(DATE_ADD(NOW(), INTERVAL 2 DAY)),
    ',      SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 3, totalViews, 0)) AS ', DAYNAME(DATE_ADD(NOW(), INTERVAL 3 DAY)),
    ',      SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 4, totalViews, 0)) AS ', DAYNAME(DATE_ADD(NOW(), INTERVAL 4 DAY)),
    ',      SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 5, totalViews, 0)) AS ', DAYNAME(DATE_ADD(NOW(), INTERVAL 5 DAY)),
    ',      SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 6, totalViews, 0)) AS ', DAYNAME(DATE_ADD(NOW(), INTERVAL 6 DAY)),
    '       FROM tmp
     GROUP BY title'));
PREPARE stmt FROM @sql;
EXECUTE stmt;

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请编辑您的问题，并提供您想要的输出示例。请参阅我问题的最后一行。该功能将为您安排好您的工作日。如果我了解您想要的结果，您需要查看数据透视。

Tag

是否与

WEEKDAY（date\u firstcall）

相同？为什么需要该列？它是我的视图表中的DAYNAME（date\u firstcall）。在这种情况下，这里不再需要，也不再有效。您不能使用来进行排序。您需要使用动态SQL来进行排序。使用调用SQL的应用程序语言可能更容易实现。SQL Server与此有什么关系？MySQL已经准备了创建动态SQL的

PREPARE

。我告诉过你我是初学者。我不知道如何在PHP中实现这一点。目前我做了以下操作：if（$result=@mysqli_query（$link，$sql））&（@mysqli_impacted_rows（$link）！==0））{$entries=array（）；而（$row=@mysqli_fetch_assoc（$result））{$entries[]=$row；}$data=json_encode（$entries）；回声（数据）；

SET @sql = (SELECT CONCAT('
     SELECT title,
            SUM(IF(WEEKDAY(date_firstcall) = WEEKDAY(NOW()), totalViews, 0)) AS ', DAYNAME(NOW()),
    ',      SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 1, totalViews, 0)) AS ', DAYNAME(DATE_ADD(NOW(), INTERVAL 1 DAY)),
    ',      SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 2, totalViews, 0)) AS ', DAYNAME(DATE_ADD(NOW(), INTERVAL 2 DAY)),
    ',      SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 3, totalViews, 0)) AS ', DAYNAME(DATE_ADD(NOW(), INTERVAL 3 DAY)),
    ',      SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 4, totalViews, 0)) AS ', DAYNAME(DATE_ADD(NOW(), INTERVAL 4 DAY)),
    ',      SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 5, totalViews, 0)) AS ', DAYNAME(DATE_ADD(NOW(), INTERVAL 5 DAY)),
    ',      SUM(IF((WEEKDAY(date_firstcall)-WEEKDAY(NOW()) % 7) = 6, totalViews, 0)) AS ', DAYNAME(DATE_ADD(NOW(), INTERVAL 6 DAY)),
    '       FROM tmp
     GROUP BY title'));
PREPARE stmt FROM @sql;
EXECUTE stmt;