Php 从laravel中的过程中获取结果-从响应中删除方括号

这是我的程序

$result = DB::select('call FastBooking(?,?)',array(Input::get('Lat'),Input::get('Long')));
return $result;

当我执行并试图返回

$result

时，我得到的结果是

[{"AutoId":4,"DriverId":4,"distance":103.81984745881},{"AutoId":3,"DriverId":3,"distance":373.5531833859},{"AutoId":1,"DriverId":1,"distance":7528.7211073364},{"AutoId":2,"DriverId":2,"distance":7560.0258965718}]

当我试图打印（$result）时我得到以下结果

Array ( [0] => stdClass Object ( [AutoId] => 4 [DriverId] => 4 [distance] => 103.81984745881 ) [1] => stdClass Object ( [AutoId] => 3 [DriverId] => 3 [distance] => 373.5531833859 ) [2] => stdClass Object ( [AutoId] => 1 [DriverId] => 1 [distance] => 7528.7211073364 ) [3] => stdClass Object ( [AutoId] => 2 [DriverId] => 2 [distance] => 7560.0258965718 ) ) Tarrif is 1 Day is 4 Time is 4Current Date is 2015-02-26 - Count : 0

我只是想得到那份工作

{"AutoId":4,"DriverId":4,"distance":103.81984745881},{"AutoId":3,"DriverId":3,"distance":373.5531833859},{"AutoId":1,"DriverId":1,"distance":7528.7211073364},{"AutoId":2,"DriverId":2,"distance":7560.0258965718}

也就是说我不想把方括号放在外面

我怎么会这样

---

（不关心解码，我只想删除这里的

[]

方括号）

我看不出为什么有人想要一个断开的json字符串，但你可以尝试这样做

str_replace (array('[', ']'), '' , $data);

---

我不确定您使用这些数据的目的，但我强烈建议您保留有效的json

您有一个对象数组。外部的括号是解码所必需的。不，我不直接解码这个，我有另一组对象，我将插入其中，所以我只需要删除

[]

，对于这种情况，得到相同的结果：（

：[{“AutoId”：4，“DriverId”：4，“distance”：103.81984745881}，{“AutoId”：3，“DriverId”：3，“distance”：373.5531833859}，{“AutoId”：1，“DriverId”：1，“distance”：7528.7211073364}，{“AutoId”：2，“DriverId”：2，“distance”：7560.0258965718}]