Php 依关系排序
我有以下数据库:Php 依关系排序,php,mysql,sql,yii,yii2,Php,Mysql,Sql,Yii,Yii2,我有以下数据库: day: id task: id day_task: day_id, task_id, weight 现在,我想获取特定日期中按重量排序的所有任务 public function getTasks() { return $this->hasMany(Task::className(), ['id' => 'task_id'])->viaTable('day_task', ['day_id' => 'id'], function ($query)
day: id
task: id
day_task: day_id, task_id, weight
现在,我想获取特定日期中按重量排序的所有任务
public function getTasks()
{
return $this->hasMany(Task::className(), ['id' => 'task_id'])->viaTable('day_task', ['day_id' => 'id'], function ($query) {
$query->orderBy(['weight' => SORT_ASC]);
});
}
导致:
SELECT * FROM `day_task` WHERE `day_id`=2 ORDER BY `weight`
SELECT * FROM `task` WHERE `id` IN ('2', '1', '3', '4')
问题是DBMS返回存储在表中的行,而不考虑in的顺序,因此我得到的是“1”、“2”、“3”、“4”,而不是“2”、“1”、“3”、“4”
除了逐行手动获取外,我找不到任何解决方案。我没有测试此问题:
// in class Day:
public function getTasks() {
return Task::find()
->leftJoin('day_task', 'task.id=day_task.task_id')
->where(['day_task.day_id' => $this->id])
->orderBy(['day_task.weight' => SORT_ASC]);
}
这将导致如下查询:
选择任务。*
从任务左侧加入task.id上的day\u任务=day\u task.task\u id
其中day_task.day_id=
按天订购\u任务重量ASC
这是真的吗?尝试在查询结束时添加orderBy
public function getTasks()
{
return $this->hasMany(Task::className(), ['id' => 'task_id'])- >viaTable('day_task', ['day_id' => 'id'])->orderBy(['weight' => SORT_ASC];
}
请检查这个是的,我知道这一点,但我不知道如何将其应用于Yii