用php构建表单_Php_Html_Mysql - Fatal编程技术网

用php构建表单

php html mysql

用php构建表单,php,html,mysql,Php,Html,Mysql,我正在建立一个小型库存系统，并希望有一个下拉菜单，供用户选择一个部分，然后输入该部分的金额。我将用mySQL数据库中的元素填充下拉菜单。我熟悉mySQL，不太熟悉php和html，但我用java编程，所以我有一些编码经验。不管怎样，这是代码，我目前的问题是其他项目只是没有出现在下拉菜单中 <form action="index.php" method="post"> <select> <!-- php code to

我正在建立一个小型库存系统，并希望有一个下拉菜单，供用户选择一个部分，然后输入该部分的金额。我将用mySQL数据库中的元素填充下拉菜单。我熟悉mySQL，不太熟悉php和html，但我用java编程，所以我有一些编码经验。不管怎样，这是代码，我目前的问题是其他项目只是没有出现在下拉菜单中

    <form action="index.php" method="post">
        <select> 
            <!-- php code to get all items -->
            <?php

                $conn = mysqli_connect("localhost", "root", "root", "inventory");

                if(mysqli_connect_errno($conn)) {
                    echo "ERROR: " . mysqli_connect_error();
                }

                $sql = "SELECT * FROM item_names";
                $result = mysql_query($sql);
                while($row = mysql_fetch_array($result)) {
                    echo '<option value="$row[name]"> $row[name] </option>';

                }
            ?>

            <option value="laptop"> Laptop </option>
            <option value="ipad"> iPad </option> 
        </select>

        Amount: <input type="text" name="amount" size="5" />

        <input type="submit" value="Enter" />

    </form>


    <form action="new.php" method="post">
        Name: <input type="text" name="name" />
        <input type="submit" value="New..." />
    </form>

    <br><br><br><br><br>

    <h3> Inventory: </h3>
    <table border="1">
    <!-- php code to fill table -->
        <tr>
            <td>(0, 0)</td>
        <tr>
        <tr>
            <td>(1, 0)</td>
        <tr>
    </table>

</body>

关于代码的任何其他建议都将非常棒，谢谢

    <form action="index.php" method="post">
        <select> 
            <!-- php code to get all items -->
            <?php

                $conn = mysqli_connect("localhost", "root", "root", "inventory");

                if(mysqli_connect_errno($conn)) {
                    echo "ERROR: " . mysqli_connect_error();
                }

                $sql = "SELECT * FROM item_names";
                $result = mysql_query($sql);
                while($row = mysql_fetch_array($result)) {
                    echo '<option value="$row[name]"> $row[name] </option>';

                }
            ?>

            <option value="laptop"> Laptop </option>
            <option value="ipad"> iPad </option> 
        </select>

        Amount: <input type="text" name="amount" size="5" />

        <input type="submit" value="Enter" />

    </form>


    <form action="new.php" method="post">
        Name: <input type="text" name="name" />
        <input type="submit" value="New..." />
    </form>

    <br><br><br><br><br>

    <h3> Inventory: </h3>
    <table border="1">
    <!-- php code to fill table -->
        <tr>
            <td>(0, 0)</td>
        <tr>
        <tr>
            <td>(1, 0)</td>
        <tr>
    </table>

</body>

代码：

    <html>
<body>


    <form action="index.php" method="post">
        <select> 
            <!-- php code to get all items -->
            <?php

                $conn = mysqli_connect("localhost", "root", "root", "inventory");

                if(mysqli_connect_errno($conn)) {
                    echo "ERROR: " . mysqli_connect_error();
                }

                $sql = "SELECT * FROM item_names";
                echo $sql;
                while($row = mysql_fetch_array($sql)) {
                    echo '<option value="$row[name]"> $row[name] </option>';

                }
            ?>

            <option value="laptop"> Laptop </option>
            <option value="ipad"> iPad </option> 
        </select>

        Amount: <input type="text" name="amount" size="5" />

        <input type="submit" value="Enter" />

    </form>


    <form action="new.php" method="post">
        Name: <input type="text" name="name" />
        <input type="submit" value="New..." />
    </form>

    <br><br><br><br><br>

    <h3> Inventory: </h3>
    <table border="1">
    <!-- php code to fill table -->
        <tr>
            <td>(0, 0)</td>
        <tr>
        <tr>
            <td>(1, 0)</td>
        <tr>
    </table>

</body>

    <form action="index.php" method="post">
        <select> 
            <!-- php code to get all items -->
            <?php

                $conn = mysqli_connect("localhost", "root", "root", "inventory");

                if(mysqli_connect_errno($conn)) {
                    echo "ERROR: " . mysqli_connect_error();
                }

                $sql = "SELECT * FROM item_names";
                $result = mysql_query($sql);
                while($row = mysql_fetch_array($result)) {
                    echo '<option value="$row[name]"> $row[name] </option>';

                }
            ?>

            <option value="laptop"> Laptop </option>
            <option value="ipad"> iPad </option> 
        </select>

        Amount: <input type="text" name="amount" size="5" />

        <input type="submit" value="Enter" />

    </form>


    <form action="new.php" method="post">
        Name: <input type="text" name="name" />
        <input type="submit" value="New..." />
    </form>

    <br><br><br><br><br>

    <h3> Inventory: </h3>
    <table border="1">
    <!-- php code to fill table -->
        <tr>
            <td>(0, 0)</td>
        <tr>
        <tr>
            <td>(1, 0)</td>
        <tr>
    </table>

</body>


笔记本电脑
iPad
数量：
姓名：






库存：
(0, 0)
(1, 0)

如果你试试这个，也许

 echo '<option value="'.$row['name'].'">' .$row['name']. '</option>';

    <form action="index.php" method="post">
        <select> 
            <!-- php code to get all items -->
            <?php

                $conn = mysqli_connect("localhost", "root", "root", "inventory");

                if(mysqli_connect_errno($conn)) {
                    echo "ERROR: " . mysqli_connect_error();
                }

                $sql = "SELECT * FROM item_names";
                $result = mysql_query($sql);
                while($row = mysql_fetch_array($result)) {
                    echo '<option value="$row[name]"> $row[name] </option>';

                }
            ?>

            <option value="laptop"> Laptop </option>
            <option value="ipad"> iPad </option> 
        </select>

        Amount: <input type="text" name="amount" size="5" />

        <input type="submit" value="Enter" />

    </form>


    <form action="new.php" method="post">
        Name: <input type="text" name="name" />
        <input type="submit" value="New..." />
    </form>

    <br><br><br><br><br>

    <h3> Inventory: </h3>
    <table border="1">
    <!-- php code to fill table -->
        <tr>
            <td>(0, 0)</td>
        <tr>
        <tr>
            <td>(1, 0)</td>
        <tr>
    </table>

</body>

echo'.$row['name'].'；

试试这个

    <form action="index.php" method="post">
        <select> 
            <!-- php code to get all items -->
            <?php

                $conn = mysqli_connect("localhost", "root", "root", "inventory");

                if(mysqli_connect_errno($conn)) {
                    echo "ERROR: " . mysqli_connect_error();
                }

                $sql = "SELECT * FROM item_names";
                $result = mysql_query($sql);
                while($row = mysql_fetch_array($result)) {
                    echo '<option value="$row[name]"> $row[name] </option>';

                }
            ?>

            <option value="laptop"> Laptop </option>
            <option value="ipad"> iPad </option> 
        </select>

        Amount: <input type="text" name="amount" size="5" />

        <input type="submit" value="Enter" />

    </form>


    <form action="new.php" method="post">
        Name: <input type="text" name="name" />
        <input type="submit" value="New..." />
    </form>

    <br><br><br><br><br>

    <h3> Inventory: </h3>
    <table border="1">
    <!-- php code to fill table -->
        <tr>
            <td>(0, 0)</td>
        <tr>
        <tr>
            <td>(1, 0)</td>
        <tr>
    </table>

</body>


笔记本电脑
iPad
数量：
姓名：






库存：
(0, 0)
(1, 0)

混合使用

mysql

和

mysqli

函数

无需

回显$sql

不解析使用单引号构建的字符串，并且不会发现该字符串中的变量。使用带有正确转义或连接的双引号

访问不带引号的数组键（

$row[name]

）是一种不好的做法

实际上，您没有在sql上运行

mysqli\u查询

，并且尽量不要混淆

mysql

和

mysqli

函数

mysql

，

mysqli

-您使用的是什么库，嗯？删除

echo$sql

。下面有一个正确的答案，在while中回音。混合使用mysqli_u和mysql_u可能是不明智的。我还建议将html和php分开，因为本网站上的许多问题都与代码混乱导致的编码错误有关。

    <form action="index.php" method="post">
        <select> 
            <!-- php code to get all items -->
            <?php

                $conn = mysqli_connect("localhost", "root", "root", "inventory");

                if(mysqli_connect_errno($conn)) {
                    echo "ERROR: " . mysqli_connect_error();
                }

                $sql = "SELECT * FROM item_names";
                $result = mysql_query($sql);
                while($row = mysql_fetch_array($result)) {
                    echo '<option value="$row[name]"> $row[name] </option>';

                }
            ?>

            <option value="laptop"> Laptop </option>
            <option value="ipad"> iPad </option> 
        </select>

        Amount: <input type="text" name="amount" size="5" />

        <input type="submit" value="Enter" />

    </form>


    <form action="new.php" method="post">
        Name: <input type="text" name="name" />
        <input type="submit" value="New..." />
    </form>

    <br><br><br><br><br>

    <h3> Inventory: </h3>
    <table border="1">
    <!-- php code to fill table -->
        <tr>
            <td>(0, 0)</td>
        <tr>
        <tr>
            <td>(1, 0)</td>
        <tr>
    </table>

</body>