Php 有人能解释一下$flipCount是如何工作的吗?
我在理解以下递归代码时遇到一些问题:Php 有人能解释一下$flipCount是如何工作的吗?,php,Php,我在理解以下递归代码时遇到一些问题: <!DOCTYPE html> <html> <head> <link type='text/css' rel='stylesheet' href='style.css'/> <title>More Coin Flips</title> </head> <body>
<!DOCTYPE html>
<html>
<head>
<link type='text/css' rel='stylesheet' href='style.css'/>
<title>More Coin Flips</title>
</head>
<body>
<p>We will keep flipping a coin as long as the result is heads!</p>
<?php
$flipCount = 0;
do {
$flip = rand(0,1);
$flipCount ++;
if ($flip){
echo "<div class=\"coin\">H</div>";
}
else {
echo "<div class=\"coin\">T</div>";
}
} while ($flip);
$verb = "were";
$last = "flips";
if ($flipCount == 1) {
$verb = "was";
$last = "flip";
}
echo "<p>There {$verb} {$flipCount} {$last}!</p>";
?>
</body>enter code here
</html>
更多的投币
只要结果是正面的,我们将继续掷硬币
在这里输入代码
$flipCount
如何获取$flip
的数量?我不明白怎么解释,有人能解释一下吗?嗯。。。由于$flipCount++
,这相当于$flipCount=$flipCount+1
?上述代码中没有递归……否则,“$flipCount==1”是什么意思?