Php 从内部循环中断循环

我有这样的数组，我用它来生成循环。我想打破循环，当它们有值“AM”时，我怎么能做到

Array
(
    [0] => A
    [1] => B
    [2] => C
    [3] => D
    [4] => E
    [5] => F
    [6] => G
    [7] => H
    [8] => I
    [9] => J
    [10] => K
    [11] => L
    [12] => M
    [13] => N
    [14] => O
    [15] => P
    [16] => Q
    [17] => R
    [18] => S
    [19] => T
    [20] => U
    [21] => V
    [22] => W
    [23] => X
    [24] => Y
    [25] => Z
    [26] => AA
    [27] => AB
    [28] => AC
    [29] => AD
    [30] => AE
    [31] => AF
    [32] => AG
    [33] => AH
    [34] => AI
    [35] => AJ
    [36] => AK
    [37] => AL
    [38] => AM
    [39] => AN
    [40] => AO
    [41] => AP
    ...
    [726] => ZZ
)

这是我的语法

$alp = range("A","Z");
$hit = count(range("A","Z"));
for($i=0; $i < count(range("A","Z")); $i++) { 
    for ($i2=0; $i2 < count(range("A","Z")); $i2++) { 

        $alp[$hit++] = $alp[$i].$alp[$i2];
         if($alp[$hit] == "AM"){
            break;
           }

    }
    $hit++;
};

$alp=范围（“A”、“Z”）；
$hit=计数（范围（“A”、“Z”））；
对于（$i=0；$i

我得到了一个错误，比如未定义的偏移量等等，直到循环结束，当我在循环中中断循环时，如何中断所有循环

在您的代码中：

 $alp[$hit++] = $alp[$i].$alp[$i2];
 // $hit is already increased.
 // Therefore `$alp[$hit]` does not exist
 if($alp[$hit] == "AM"){
    break;
 }

替换为以下内容：

 $alp[$hit] = $alp[$i].$alp[$i2];
 // $hit is still the same
 if($alp[$hit] == "AM"){
    // `break` will stop inner `for` loop (with $i2)
    break;
    // use `break 2;` to break both `for` loops
 }
 $hit++;

在代码中：

 $alp[$hit++] = $alp[$i].$alp[$i2];
 // $hit is already increased.
 // Therefore `$alp[$hit]` does not exist
 if($alp[$hit] == "AM"){
    break;
 }

替换为以下内容：

 $alp[$hit] = $alp[$i].$alp[$i2];
 // $hit is still the same
 if($alp[$hit] == "AM"){
    // `break` will stop inner `for` loop (with $i2)
    break;
    // use `break 2;` to break both `for` loops
 }
 $hit++;

你的代码

 $alp[$hit++] = $alp[$i].$alp[$i2];
 // In $alp array you have any 26 items as per your count.
 // here $hit is 27 and in your $alp there is only 26.
 // so you just need to push the new variables in and then check

 array_push($alp,$alp[$i].$alp[$i2]);

 // Now check `$alp[$hit]`.
 if($alp[$hit] == "AM"){
    break;
 }

试试这个代码

$alp = range("A","Z");
$hit = count(range("A","Z"));

for($i=0; $i < count(range("A","Z")); $i++) { 
    for ($i2=0; $i2 < count(range("A","Z")); $i2++) { 

        array_push($alp, $alp[$i].$alp[$i2]);

        if($alp[$hit] == "AM"){
            // echo $alp[$hit];
            // Here is the First Break
            break 2; // it breaks all loops;
        }
    }
    $hit++;
};

$alp=范围（“A”、“Z”）；
$hit=计数（范围（“A”、“Z”））；
对于（$i=0；$i

您需要编码

 $alp[$hit++] = $alp[$i].$alp[$i2];
 // In $alp array you have any 26 items as per your count.
 // here $hit is 27 and in your $alp there is only 26.
 // so you just need to push the new variables in and then check

 array_push($alp,$alp[$i].$alp[$i2]);

 // Now check `$alp[$hit]`.
 if($alp[$hit] == "AM"){
    break;
 }

试试这个代码

$alp = range("A","Z");
$hit = count(range("A","Z"));

for($i=0; $i < count(range("A","Z")); $i++) { 
    for ($i2=0; $i2 < count(range("A","Z")); $i2++) { 

        array_push($alp, $alp[$i].$alp[$i2]);

        if($alp[$hit] == "AM"){
            // echo $alp[$hit];
            // Here is the First Break
            break 2; // it breaks all loops;
        }
    }
    $hit++;
};

$alp=范围（“A”、“Z”）；
$hit=计数（范围（“A”、“Z”））；
对于（$i=0；$i

它没有同时中断两个循环使用

中断2

而不是第二个循环中的

break

。仍然不工作，它是循环直到

[676]=>ZZ

，我想如果

$alp[$hit]==“AM”

，然后断开，所以它只有37个键。它没有同时断开两个循环使用

break 2

而不是第二个循环中的

break

。仍然不工作，它是循环直到

[676]=>ZZ

，我想如果

$alp[$hit]==“AM”

，然后break，所以它只有37键