Php 一网打尽

我正在学习PHP，现在正在创建一个多合一web表单，将新的订户记录添加到新闻稿数据库的订户表中。这是我第一次访问这个网站，所以请原谅我的错误

注释解释了决定是否处理表单的代码部分。我不确定它是否需要进入验证提交表单数据的if..else语句内部，或者它是否在自己的if..else中进行验证

当我将它放入验证中时，html表单会显示出来，但当我点击submit时，所有信息都会刷新，什么也不会发生

当我把它放在验证之后，html表单没有显示，我得到一个错误，说未定义变量：FormErrorCount。然后它告诉我应该获得的id号，但我没有输入姓名或电子邮件（由于html表单未显示），这是空白的

有一个包含文件，但这很好

我相信一旦我弄明白了，我会有想扇自己一巴掌的感觉，但我盯着屏幕看的时间太长了。多谢各位

<?php

    $ShowForm = FALSE;
    $SubscriberName = "";
    $SubscriberEmail = "";

    if (isset($_POST['submit'])) {
        $FormErrorCount = 0;
        if (isset($_POST['SubName'])) {
            $SubscriberName = stripslashes($_POST['SubName']);
            $SubscriberName = trim($SubscriberName);
            if (strlen($SubscriberName) == 0) {
                echo "<p>You must include your name</p>\n";
                ++$FormErrorCount;
            }
        }else{
            echo "<p>Form submittal error (No 'SubName' field)!</p>\n";
            ++$FormErrorCount;
        }
        if (isset($_POST['SubEmail'])) {
            $SubscriberEmail = stripslashes($_POST['SubEmail']);
            $SubscriberEmail = trim($SubscriberEmail);
            if (strlen($SubscriberEmail == 0)) {
                echo "<p>You must include your email address!</p>\n";
                ++$FormErrorCount;
            }
        }else{
            echo "<p>Form submittal error (No 'SubEmail' field)!</p>\n";
            ++$FormErrorCount;
        }
        //CODE BELOW IS THE SAME AS THE COMMENTED OUT CODE TOWARDS THE END. NOT SURE WHERE IT GOES.

        if ($FormErrorCount == 0) {
            $ShowForm = FALSE;
            include("inc_db_newsletter.php");
            if ($DBConnect !== FALSE) {
                $TableName = "subscribers";
                $SubscriberDate = date("Y-m-d");
                $SQLstring = "INSERT INTO $TableName " .
                             " (name, email, subscribe_date) " .
                             " VALUES('$SubscriberName', '$SubscriberEmail', '$SubscriberDate')";
                $QueryResult = @mysql_query($SQLstring, $DBConnect);
                if ($QueryResult === FALSE) {
                    echo "<p>Unable to insert the values into the subscriber table.</p>" .
                        "<p>Error code " . mysql_errno($DBConnect) . ": " .
                        mysql_error($DBConnect) . "</p>";
                }else{
                $SubscriberID = mysql_insert_id($DBConnect);
                echo "<p>" . htmlentities($SubscriberName) . ", you are now subscribed to our
                     newsletter.<br />";
                echo "Your subscriber ID is $SubscriberID.<br />";
                echo "Your email address is " . htmlentities($SubscriberEmail) . ".</p>";
                }
                mysql_close($DBConnect);              
            }
        }else{
            $ShowForm = TRUE;
        }

        //CODE ABOVE IS THE SAME AS THE COMMENTED OUT CODE TOWARDS THE END. NOT SURE WHERE IT GOES.
    }else{
        $ShowForm = TRUE;
    }

    /* CODE BELOW IS SAME AS THE CODE BETWEEN THE COMMENTS ABOVE, BUT NOT SURE WHERE IT BELONGS

    if ($FormErrorCount == 0) {
        $ShowForm = FALSE;
        include("inc_db_newsletter.php");
        if ($DBConnect !== FALSE) {
            $TableName = "subscribers";
            $SubscriberDate = date("Y-m-d");
            $SQLstring = "INSERT INTO $TableName (name, email, subscribe_date) " .
                         "VALUES ('$SubscriberName', '$SubscriberEmail', '$SubscriberDate')";
            $QueryResult = @mysql_query($SQLstring, $DBConnect);
            if ($QueryResult === FALSE) {
                echo "<p>Unable to insert the values into the subscriber table.</p>" .
                     "<p>Error code " . mysql_errno($DBConnect) . ": " .
                     mysql_error($DBConnect) . "</p>";
            }else{
                $SubscriberID = mysql_insert_id($DBConnect);
                echo "<p>" . htmlentities($SubscriberName) . ", you are now subscribed to our
                     newsletter.<br />";
                echo "Your subscriber ID is $SubscriberID.<br />";
                echo "Your email address is " . htmlentities($SubscriberEmail) . ".</p>";
            }
            mysql_close($DBConnect);              
        }
    }else{
        $ShowForm = TRUE;
    }

    */CODE ABOVE IS SAME AS THE CODE BETWEEN THE COMMENTS ABOVE SECTION, BUT NOT SURE WHERE IT BELONGS

//HTML PORTION  
    if ($ShowForm) {
        ?>
        <form action = "NewsletterSubscribe.php" method = "POST">
            <p><strong>Your Name: </strong>
                <input type = "text" name = "SubName" value = "<?php echo $SubscriberName; ?>" /></p>
            <p><strong>Your Email Address: </strong>
                <input type = "text" name = "SubEmail" value = "<?php echo $SubscriberEmail; ?>" /></p>
            <p><input type = "Submit" name = "Submit" value = "Submit" /></p>
        </form>
        <?php
    }

?>

---

您的代码（暂时忽略最后的ShowForm部分）的结构如下：

if this is a submit {
    validate the form data
    if there are no errors {
        save the form data
    }
}

这看起来很合理。也许你的表格不是作为帖子提交的？检查您的
，并使用Firebug确保表单数据正在提交

如果要移动错误检查，则必须：

if this is a submit {
    validate the form data
}
if there are no errors {
    save the form data
}

这是错误的，因为如果表单没有被提交，那么您就不会有错误（因此出现“undefined variable”错误），然后它会尝试保存不存在的表单数据。
运行var_dump（$SQLstring）以查看1。如果你已经到了那一步，那么2。您的查询内容究竟是什么。这是调试的良好起点。