使用PHP从url处理json响应

我在我的网站上使用zillow api

{
request: {
address: "13546 36th Ave NE",
citystatezip: "Seattle, WA"
},
message: {
text: "Request successfully processed",
code: "0"
},
response: {
results: {
result: {
zpid: "48897608",
links: {
homedetails: "http://www.zillow.com/homedetails/13546-36th-Ave-NE-Seattle-WA-98125/48897608_zpid/",
graphsanddata: "http://www.zillow.com/homedetails/13546-36th-Ave-NE-Seattle-WA-98125/48897608_zpid/#charts-and-data",
mapthishome: "http://www.zillow.com/homes/48897608_zpid/",
comparables: "http://www.zillow.com/homes/comps/48897608_zpid/"
},
address: {
street: "13546 36th Ave NE",
zipcode: "98125",
city: "Seattle",
state: "WA",
latitude: "47.727631",
longitude: "-122.289193"
},
zestimate: {
amount: "393735",
last-updated: "03/12/2017",
oneWeekChange: {
@attributes: {
deprecated: "true"
}
},
valueChange: "24606",
valuationRange: {
low: "374048",
high: "413422"
},
percentile: "0"
},
localRealEstate: {
region: {
@attributes: {
name: "Cedar Park",
id: "271831",
type: "neighborhood"
},
zindexValue: "547,700",
links: {
overview: "http://www.zillow.com/local-info/WA-Seattle/Cedar-Park/r_271831/",
forSaleByOwner: "http://www.zillow.com/cedar-park-seattle-wa/fsbo/",
forSale: "http://www.zillow.com/cedar-park-seattle-wa/"
}
}
}
}
}
}
}

上面是我从Zillow Api得到的响应，我从响应中获取了值，如下所示：

zpid => 48897608
links:
homedetails => http://www.zillow.com/homedetails/13546-36th-Ave-NE-Seattle-WA-98125/48897608_zpid/
graphsanddata => http://www.zillow.com/homedetails/13546-36th-Ave-NE-Seattle-WA-98125/48897608_zpid/#charts-and-data
mapthishome => http://www.zillow.com/homes/48897608_zpid/
comparables => http://www.zillow.com/homes/comps/48897608_zpid/
address:
street => 13546 36th Ave NE
zipcode => 98125
city => Seattle
state => WA
latitude => 47.727631
longitude => -122.289193
zestimate:
amount => 393735
last-updated => 03/12/2017

我使用下面的代码获得了这个结果：

$jsonIterator = new RecursiveIteratorIterator(
    new RecursiveArrayIterator(json_decode($json, TRUE)),
    RecursiveIteratorIterator::SELF_FIRST);

foreach ($jsonIterator as $key => $val) {
    if(is_array($val)) {
        echo "$key:\n";
    } else {
        echo "$key => $val\n";
    }
}

现在我的问题是如何获得如下格式的单个值

<li>zipid:48897608</li>
<li>low:374048</li>

<li>last-updated:03/12/2017</li>

zipid:48897608

低：374048

最后更新日期：2017年3月12日

---

这是因为列表标记在页面上被处理为html标记。换句话说，它不是作为纯文本处理的。 在这种情况下，我们应该将“”替换为“<”和“>”

这是代码行

foreach ($arr as $key=>$val) {
    echo "&ltli&gt{$key}:{$val}&lt/li&gt";
    echo '<br>';
}

foreach（$arr as$key=>$val）{
echo“<li>{$key}:{$val}</li>”；
回声“
”；
}

希望对你有帮助

---

谢谢大家!

我想答案在你的问题中，只要修改你的

如果
条件：

echo '<ul>';
foreach ($jsonIterator as $key => $val) {
    if(!is_array($val)) {
        echo '<li>'.$key.':'.$val.'</li>';
    } 
}
echo '</ul>';

echo'
'；
foreach（$jsonIterator作为$key=>$val）{
如果（！is_数组（$val））{
回显“
”.$key.：“.$val.
”；
} 
}
回声“
”；
你想把你的JSON转换成格式化的HTML吗？是@Ayush，把JSON转换成HTMLTry这个：
echo“
{$key}:{$val}
”。确保foreach函数之外有
。致命错误：无法将递归迭代器类型的对象用作array@C0dekid是否需要大括号（
{}
）我不想foreachi需要将值放在不同的位置，但不理解您的查询。没有循环，如何访问值？这是一个问题。