SQL查询依赖于同一页面上php中另一个查询的结果

我试图编写一个查询，从我的数据库中获取列车列表，用户将输入真实姓名，第一个查询将获取车站代码或“tiploc”，然后在第二个查询中使用它。出于某种原因，我没有得到任何回报，我确信这与从fetch获取的数据有关，因为如果我硬编码tiploc，它工作得很好。我在php方面相当弱，所以任何帮助都将是非常好的！谢谢

<?
 mysql_connect("localhost","root","XXXXXX")
or die ("No connection could be made to the OpenRail 
Database");mysql_select_db("autotrain");

$query1 = "SELECT tiploc_code FROM allstations WHERE c LIKE 'Cradley Heath';";

$result1 =mysql_query($query1);


$tiploc=null;
while($row = mysql_fetch_assoc($result1)){
$tipoc=$row['tiploc_code'];

}
$query2 = "SELECT allstations.C, locations.public_departure
FROM `locations` , allstations, schedules_cache,schedules
WHERE locations.id = schedules_cache.id
AND schedules_cache.id = schedules.id
AND '2012-11-11' BETWEEN schedules.date_from AND schedules.date_to
AND locations.tiploc_code = '$tiploc'
AND locations.public_departure >=1600
AND locations.public_departure <=1700
AND schedules.runs_su LIKE '1'
AND schedules_cache.destination = allstations.tiploc_code
ORDER BY locations.public_departure ASC;";

$result2=mysql_query($query2);

while($row = mysql_fetch_assoc($result2)){
echo($row['C']);

}
?>

---

如果您进入PHP手册页面，则不鼓励使用mysql\u fetch\u assoc。我假设tiploc_代码是数据库中的一个字段。因此，当您查询数据库时，它将返回一个对象。你可以用

$tipoc = $reuslt1[0]->tiploc_code

如果只有一排。如果有多行，请使用。
$count=count（$result1）

（$i=0；$itiploc\U代码）的

$query2=“选择allstations.C，locations.public\u出发
从'locations'，allstations，schedules\u cache，schedules
其中locations.id=schedules\u cache.id
和schedules_cache.id=schedules.id
和“2012-11-11”之间。日期从和日期到
和locations.tiploc\u代码=\“$tipoc\”
和位置。公共_出发>=1600
和地点。公共_出发两件事：

首先，您的代码中有一个输入错误。在第一个查询的第一个while循环中，您有一个名为$tipoc的变量，而不是$tiploc。因此，在第二个查询中不会有结果

其次，您应该将第二个查询的逻辑放入第一个查询的循环中。这样，只有在第一个查询返回结果时才执行第二个查询。如果您只希望第一个记录中有一条记录，则可以将逻辑从while循环更改为if语句，如下所示：

if($row = mysql_fetch_assoc($result1)){
    $tiploc=$row['tiploc_code'];
    ...
    include your second query here inside the if statement.

您正在覆盖$tipoc=$row['tiploc_code']

请尝试以下代码

<?
 mysql_connect("localhost","root","Boeing1992")
or die ("No connection could be made to the OpenRail 
Database");mysql_select_db("autotrain");

$query1 = "SELECT tiploc_code FROM allstations WHERE c LIKE 'Cradley Heath';";

$result1 =mysql_query($query1);


$tiploc=null;
$tipocArr = array();
while($row = mysql_fetch_assoc($result1)){
$tipocArr[] =$row['tiploc_code'];

}
$tipoc = implode(",",$tipocArr);

$query2 = "SELECT allstations.C, locations.public_departure
FROM `locations` , allstations, schedules_cache,schedules
WHERE locations.id = schedules_cache.id
AND schedules_cache.id = schedules.id
AND '2012-11-11' BETWEEN schedules.date_from AND schedules.date_to
AND locations.tiploc_code IN '$tiploc'
AND locations.public_departure >=1600
AND locations.public_departure <=1700
AND schedules.runs_su LIKE '1'
AND schedules_cache.destination = allstations.tiploc_code
ORDER BY locations.public_departure ASC;";

$result2=mysql_query($query2);

while($row = mysql_fetch_assoc($result2)){
echo($row['C']);

}
?>

我真的希望这不是你真正的数据库密码=o\ahhh，谢谢，尽管这个特定的示例仅在一台机器上本地，无法在外部访问。谢谢！很有魅力，是的，它只有一行。
<?
 mysql_connect("localhost","root","Boeing1992")
or die ("No connection could be made to the OpenRail 
Database");mysql_select_db("autotrain");

$query1 = "SELECT tiploc_code FROM allstations WHERE c LIKE 'Cradley Heath';";

$result1 =mysql_query($query1);


$tiploc=null;
$tipocArr = array();
while($row = mysql_fetch_assoc($result1)){
$tipocArr[] =$row['tiploc_code'];

}
$tipoc = implode(",",$tipocArr);

$query2 = "SELECT allstations.C, locations.public_departure
FROM `locations` , allstations, schedules_cache,schedules
WHERE locations.id = schedules_cache.id
AND schedules_cache.id = schedules.id
AND '2012-11-11' BETWEEN schedules.date_from AND schedules.date_to
AND locations.tiploc_code IN '$tiploc'
AND locations.public_departure >=1600
AND locations.public_departure <=1700
AND schedules.runs_su LIKE '1'
AND schedules_cache.destination = allstations.tiploc_code
ORDER BY locations.public_departure ASC;";

$result2=mysql_query($query2);

while($row = mysql_fetch_assoc($result2)){
echo($row['C']);

}
?>