Php 从包含不同和不相关信息的多个表中获取mysql搜索结果

我一直在与一位客户合作，并不断回到这个查询问题，试图找到一个解决方案，我一直在谷歌搜索，但没有找到相关的结果

我的客户有多种旅游服务，如游轮、海滩度假村、酒店、船舱等

我已经更新了所有单独的搜索页面，并一直在努力使组合搜索页面正常工作

旅行社的表是完全不相关的，并且没有共享许多字段名

在组合搜索页面上，我尝试根据用户搜索词从多个表中获取搜索结果。因此，如果用户输入“夏威夷”作为搜索词，他们应该会看到夏威夷作为停靠港的邮轮、夏威夷的酒店、夏威夷的海滩度假村等的搜索结果

例如，这里有3个表（简化后，live站点上还有许多其他字段）：

表3：

+----+--------------+-------------+-------+------+
| id | cruise_name  | destination | price | deck |
+----+--------------+-------------+-------+------+
|  1 | royal cruise | Hawaii      | 1000  | 1    |
|  2 | crown cruise | St. Martin  | 1200  | 2    |
+----+--------------+-------------+-------+------+

餐桌酒店：

+----+--------------+-------------+-------+------+
| id | hotel_name   | location    | price | beds |
+----+--------------+-------------+-------+------+
|  1 | sheraton     | Hawaii      | 139   | 2    |
|  2 | meriott      | Florida     | 75    | 2    |
+----+--------------+-------------+-------+------+

Table度假村：

+----+--------------+-------------+-------+-----------+
| id | resort       | location    | price | room_type |
+----+--------------+-------------+-------+-----------+
|  1 | sandals      | Jamaica     | 2000  | 3         |
|  2 | dream resort | Hawaii      | 2300  | 1         |
+----+--------------+-------------+-------+-----------+

作为一个简单的例子，假设我是一个用户搜索“夏威夷”，我需要向他们显示上面每个表的结果

我得到的最接近的查询如下：

SELECT  
    cuises.id AS cruise_id, 
    cuises.cruise_name AS cruise_cruise_name, 
    cuises.destination AS cruise_destination, 
    cuises.price AS cruise_price, 
    cuises.deck AS cruise_deck, 

    hotels.id AS hotels_id, 
    hotels.hotel_name AS hotels_hotel_name, 
    hotels.location AS hotels_location, 
    hotels.price AS hotels_price,
    hotels.beds AS hotels_beds,

    resorts.id AS resorts_id, 
    resorts.resort AS resorts_resort, 
    resorts.location AS resorts_location, 
    resorts.price AS resorts_price,
    resorts.room_type AS resorts_room_type

FROM 
    cuises,
    hotels,
    vacation_packages,
    resorts 

WHERE 
    (cuises.cruise_name LIKE '%Hawaii%') OR
    (hotels.hotel_name LIKE '%Hawaii%') OR
    (resorts.resort LIKE '%Hawaii%')                      

上面的样式查询将结果混合到包含多个表数据的行中，我要查找的是每行仅包含一个选项卡信息的行

我希望psuedo选项卡在查询中看起来像这样，这样我就可以轻松地用PHP解析结果：

+-----------+---------------------+--------------------+--------------+-------------+-----------+---------------------+--------------------+--------------+-------------+------------+----------------------+---------------------+---------------+-------------------+
| cruise_id | cruise_cruise_name  | cruise_destination | cruise_price | cruise_deck | hotels_id | hotels_hotel_name   | hotels_location    | hotels_price | hotels_beds | resorts_id | resorts_resort       | resorts_location    | resorts_price | resorts_room_type |
+-----------+---------------------+--------------------+--------------+-------------+-----------+---------------------+--------------------+--------------+-------------+------------+----------------------+---------------------+---------------+-------------------+
|  1        | royal cruise        | Hawaii             | 1000         | 1           |           |                     |                    |              |             |            |                      |                     |               |                   |
|  2        | crown cruise        | St. Martin         | 1200         | 2           |           |                     |                    |              |             |            |                      |                     |               |                   |
|           |                     |                    |              |             |  1        | sheraton            | Hawaii             | 139          | 2           |            |                      |                     |               |                   |
|           |                     |                    |              |             |  2        | meriott             | Florida            | 75           | 2           |            |                      |                     |               |                   |
|           |                     |                    |              |             |           |                     |                    |              |             |  1         | sandals              | Jamaica             | 2000          | 3                 |
|           |                     |                    |              |             |           |                     |                    |              |             |  2         | dream resort         | Hawaii              | 2300          | 1                 |
+-----------+---------------------+--------------------+--------------+-------------+-----------+---------------------+--------------------+--------------+-------------+------------+----------------------+---------------------+---------------+-------------------+

基本上，如果我可以在多个表中组合我的搜索结果，它们的字段如上表所示放在一起，度假村的字段在包含酒店等信息的行中为空。然后我可以轻松使用LIMIT和OFFSET对返回的数据进行分页，并使用PHP将返回的信息作为数组进行循环，并根据id字段（该字段不为空）确定行中的旅行社，以使用适当的模板显示该行的信息

有没有一种方法可以查询多个选项卡，并将它们的行合并到一个结果集中，而不会混淆它们的数据？

如果需要，这将对每个表进行单独选择，并将所有结果合并到一个查询中。union查询的规定是，所有union查询必须返回相同数量的列，因此您需要

从每个子查询中的所有其他表中选择null作为fieldname

：

SELECT * FROM (
    (SELECT  
        cuises.id AS cruise_id, 
        cuises.cruise_name AS cruise_cruise_name, 
        cuises.destination AS cruise_destination, 
        cuises.price AS cruise_price, 
        cuises.deck AS cruise_deck,
        null as hotels_id, null as hotels_hotel_name, null as hotels_location, null as hotels_price, null as hotels_beds,
        null as resorts_id, null as resorts_resort, null as resorts_location, null as resorts_price, null as resorts_room_type
    FROM cruises
    WHERE cruises.cruise_name LIKE '%Hawaii%')

    UNION ALL

    (SELECT
        null as cruise_id, null as cruise_cruise_name, null as cruise_destination, null as cruise_price, null as cruise_deck,
        hotels.id AS hotels_id, 
        hotels.hotel_name AS hotels_hotel_name, 
        hotels.location AS hotels_location, 
        hotels.price AS hotels_price,
        hotels.beds AS hotels_beds
        null as resorts_id, null as resorts_resort, null as resorts_location, null as resorts_price, null as resorts_room_type
    FROM hotels
    WHERE hotels.hotel_name LIKE '%Hawaii%')

    UNION ALL

    (SELECT
        null as cruise_id, null as cruise_cruise_name, null as cruise_destination, null as cruise_price, null as cruise_deck,
        null as hotels_id, null as hotels_hotel_name, null as hotels_location, null as hotels_price, null as hotels_beds,
        resorts.id AS resorts_id, 
        resorts.resort AS resorts_resort, 
        resorts.location AS resorts_location, 
        resorts.price AS resorts_price,
        resorts.room_type AS resorts_room_type
    FROM resorts 
    WHERE resorts.resort LIKE '%Hawaii%')
)

从这里，您可以在查询结束时轻松地对结果进行排序、筛选和限制

---

注意：我没有在此表中包括

vacation\u包

因为您没有从中选择任何内容或在特定条件下使用它。要添加它，只需使用一个新的

SELECT

语句添加另一个

UNION ALL

，您的查询是对各种属性的笛卡尔乘积。您只需要一个列表，因此，

union all

是一个不错的选择

问题是您必须为每个子选择定义所有列。讨厌。这需要输入显式的空值。下面展示了邮轮和酒店的理念：

SELECT c.id AS cruise_id, c.cruise_name AS cruise_cruise_name, c.destination AS cruise_destination, 
       c.price AS cruise_price, c.deck AS cruise_deck, 
       NULL AS hotels_id, NULL AS hotels_hotel_name, NULL AS hotels_location, 
       NULL AS hotels_price, NULL AS hotels_beds,
       . . .
FROM cruises c
WHERE cuises.cruise_name LIKE '%Hawaii%'
union all
SELECT NULL AS cruise_id, NULLAS cruise_cruise_name, NULL AS cruise_destination, 
       NULL AS cruise_price, NULL AS cruise_deck, 
       h.id AS hotels_id,  h.hotel_name AS hotels_hotel_name, h.location AS hotels_location, 
       h.price AS hotels_price, h.beds AS hotels_beds,
       . . .
FROM hotels h
WHERE hotels.hotel_name LIKE '%Hawaii%';

---

我不认为mysql可以像您希望的那样为每个表返回1行。。 我可能错了，但我不认为你真的应该希望你的数据像那样返回

我将使用

LEFT JOIN

和alaise获取所有数据，并用您正在使用的任何显示语言对其进行解析

这是这些桌子的提琴：

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谢谢！我将使用您的示例更新我的开发站点上的查询。此外，我还复制/粘贴了实际查询的一部分，并在用示例数据替换表名时错过了休假包。@rmmoul我忘记了重要部分-每个查询必须具有相同的列数，您需要为每个表中不存在的字段别名指定空值-我已经更新了答案。@scrowler的UNION ALL建议做到了这一点，还允许我将类似字段推送到共享别名中（例如，所有目标信息都位于一个字段名下）。将一些feild推到一个别名中，并为联盟生成的表提供一个临时名称，我还可以按项目名称（包含邮轮公司名称、度假村名称等，取决于从中提取的表）进行订购，这允许我按字母顺序或按价格等混合显示结果。