如何在php中形成字符串

我有一张桌子，现在我想在填好这张桌子之后 这是

ssl.php

页面中的表

<table  width="100%" border="0" cellspacing="0" cellpadding="0">
            <tr> 
            <td class="TitleBar">Generate CSR</td>
            </tr>
        </table>
     <table  cellspacing="0" border="0" width="100%">

         <tr>               
            <td>Country Name(only two letters) :</td>
            <td >
            <input name="countryname" type="text"  id="countryname" MaxLength="2"/>
            </td>
        </tr>  
        <tr>                
            <td>State or Province Name :</td>
            <td> 
            <input name="province" type="text" id="province"/>
            </td>
         </tr>
         <tr>               
        <td>Locality Name :</td>
            <td >
            <input name="localityname" type="text"  id="localityname"/>
            </td>
        <tr>                
        <td>Organization Name :</td>
            <td> 
            <input name="organizationname" type="text" class="style16" id="organizationname"/>
            </td>
         </tr> 
         <tr>           
         <td>Organizational Unit Name :</td>
                <td > 
                <input name="organizationunit" type="text" id="organizationunit"/>
                </td>
         </tr>
         <tr>               
        <td>Common Name :</td>
            <td> 
            <input name="commonname" type="text"  id="commonname"/>
            </td>
         </tr>
            <tr>                
        <td>Email Address :</td>
            <td > 
            <input name="email" type="text"  id="email"/>
            </td>
         </tr>
            <tr>
            <td style="padding-top:15px padding-bottom:10px" align="right"> 
             <input name="gencsr" type="submit"  id="button" value="Generate CSR" class="FormButton" />
            </td>

            </tr></table>

我希望我的输出如下：-

"/C=IN/ST=MAHARASHTRA/L=MUMBAI/O=Cofin Inc/OU=Sales/CN=www.coufdffin.itdpl"

发布表格后，如何以这种格式生成字符串

UPdate

现在我用这个

$dn = array("C" => "".trim($_POST['countryname']),
   "ST" => "".trim($_POST['province']),
   "L" => "".trim($_POST['localityname']),
   "O" => "".trim($_POST['organizationname']),
   "OU" => "".trim($_POST['organizationunit']),
   "CN" => "".trim($_POST['commonname']),
   "emailAddress" => "".trim($_POST['email']));
   $comma_separated = implode(",", $dn);
   echo $comma_separated;

我能做什么？请帮助我？

在一个数组中生成（C、ST、L、O、OU、CN），并在页面发布后获取post数组

---

使用内爆（）方法构造新字符串。

如果html表单中的这些字段名称正确。您可以简单地“添加”所有这些字符串。假设表单中的国家名称字段的名称是countryname。然后，PHP可以使用

$\u POST[“countryname”]

读取输入。因此，您可以像这样生成输出的第一个会话

$output = "/C=" . $_POST["countryname"]

使用。在PHP中连接不同的字符串

希望这有帮助。：）

而不是：

$dn = array("C" => "".trim($_POST['countryname']),
   "ST" => "".trim($_POST['province']),
   "L" => "".trim($_POST['localityname']),
   "O" => "".trim($_POST['organizationname']),
   "OU" => "".trim($_POST['organizationunit']),
   "CN" => "".trim($_POST['commonname']),
   "emailAddress" => "".trim($_POST['email']));
   $comma_separated = implode(",", $dn);
   echo $comma_separated;

做：

---

你有正在处理的HTML或PHP代码吗？@Kevin Hikaru Evans:）问题编辑你必须告诉我们更多关于确切边界条件的信息。这是你收到的输入吗？字段名是否始终保持不变？还有：到目前为止你都尝试了什么？@fireyedboy:）问题编辑

$dn = array("C" => "".trim($_POST['countryname']),
   "ST" => "".trim($_POST['province']),
   "L" => "".trim($_POST['localityname']),
   "O" => "".trim($_POST['organizationname']),
   "OU" => "".trim($_POST['organizationunit']),
   "CN" => "".trim($_POST['commonname']),
   "emailAddress" => "".trim($_POST['email']));
   $comma_separated = implode(",", $dn);
   echo $comma_separated;

$dn = array("C" => "".trim($_POST['countryname']),
"ST" => "".trim($_POST['province']),
"L" => "".trim($_POST['localityname']),
"O" => "".trim($_POST['organizationname']),
"OU" => "".trim($_POST['organizationunit']),
"CN" => "".trim($_POST['commonname']),
"emailAddress" => "".trim($_POST['email']));
$str = '';
foreach($dn as $key => $val){
    $str .= "/$key=$val";
}