while循环中的PHP json_encode()
我试图在while循环中使用while循环中的PHP json_encode(),php,arrays,sqlite,while-loop,json,Php,Arrays,Sqlite,While Loop,Json,我试图在while循环中使用json\u encode(),同时获取数据库结果。这是我的密码: <? $database = sqlite_open("thenew.db", 0999, $error); if(!$database) die($error); $query = "SELECT * FROM users"; $results = sqlite_query($database, $query); if(!$results) die("Canot execute query
json\u encode()
,同时获取数据库结果。这是我的密码:
<?
$database = sqlite_open("thenew.db", 0999, $error);
if(!$database) die($error);
$query = "SELECT * FROM users";
$results = sqlite_query($database, $query);
if(!$results) die("Canot execute query");
while($row = sqlite_fetch_array($results)) {
$data = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}
echo json_encode(array("response"=>$data));
sqlite_close($database);
?>
这个的输出是
{“response”:“lastUserID lastUser lastXPos lastYPos”}
我希望它是
{“回复”:[“1亚历克斯10 12”,“2弗雷德27 59”,“3汤姆47 19”]
等等
因此我希望json\u encode()
函数将所有用户放入数组,而不是最后一个。我该怎么做?谢谢你改变这个
while($row = sqlite_fetch_array($results)) {
$data = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}
到
改变这个
while($row = sqlite_fetch_array($results)) {
$data = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}
到
将每个用户推送到阵列:
$data = array();
while($row = sqlite_fetch_array($results)) {
$data[] = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}
echo json_encode(array("response"=>$data));
将每个用户推送到阵列:
$data = array();
while($row = sqlite_fetch_array($results)) {
$data[] = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}
echo json_encode(array("response"=>$data));
尝试:
试试: