Php Yii登录不工作

我是Yii PHP框架的新手，我正在尝试使用登录表单。我知道当你安装testdrive应用程序时，Yii上已经有了登录功能。我只是编辑它，通过数据库登录，它不工作。我没有任何错误的代码，但当我登录时，它总是说不正确的密码或用户名。这是我的密码

对于UserIdentity.php

class UserIdentity extends CUserIdentity
{
/**
 * Authenticates a user.
 * The example implementation makes sure if the username and password
 * are both 'demo'.
 * In practical applications, this should be changed to authenticate
 * against some persistent user identity storage (e.g. database).
 * @return boolean whether authentication succeeds.
 */
    private $_id;
    public function authenticate()
    {
        $record=User::model()->findByAttributes(array('username'=>$this->username));
        if($record===null)
          $this->errorCode=self::ERROR_USERNAME_INVALID;
        else if($record->password!==crypt($this->password,$record->password))
          $this->errorCode=self::ERROR_PASSWORD_INVALID;
        else
        {
          $this->_id=$record->id;
          $this->setState('title', $record->title);
          $this->errorCode=self::ERROR_NONE;
        }
       return !$this->errorCode;
     }

    public function getId()
    {
    return $this->_id;
    }
}

下面是SiteController.php的示例

public function actionLogin()
{
    $model=new LoginForm;

    // if it is ajax validation request
    if(isset($_POST['ajax']) && $_POST['ajax']==='login-form')
    {
        echo CActiveForm::validate($model);
        Yii::app()->end();
    }

    // collect user input data
    if(isset($_POST['LoginForm']))
    {
        $model->attributes=$_POST['LoginForm'];
        // validate user input and redirect to the previous page if valid
        if($model->validate() && $model->login())
            $this->redirect(Yii::app()->user->returnUrl);
    }
    // display the login form
    $this->render('login',array('model'=>$model));
}

---

你能帮我吗？谢谢

如果密码保存在db text plain中，请不要使用crypt

    class UserIdentity extends CUserIdentity
{
/**
 * Authenticates a user.
 * The example implementation makes sure if the username and password
 * are both 'demo'.
 * In practical applications, this should be changed to authenticate
 * against some persistent user identity storage (e.g. database).
 * @return boolean whether authentication succeeds.
 */
    private $_id;
    public function authenticate()
    {
        $record=User::model()->findByAttributes(array('username'=>$this->username));
        if($record===null)
          $this->errorCode=self::ERROR_USERNAME_INVALID;
        else if($record->password!==$this->password) // changed
          $this->errorCode=self::ERROR_PASSWORD_INVALID;
        else
        {
          $this->_id=$record->id;
          $this->setState('title', $record->title);
          $this->errorCode=self::ERROR_NONE;
        }
       return !$this->errorCode;
     }

    public function getId()
    {
    return $this->_id;
    }
}

---

在您的编码中，行

    else if($record->password!==crypt($this->password,$record->password))

正在将密码与字符串哈希进行比较（

crypt（）

生成字符串哈希/加密）

如果在数据库中保存密码而不加密，则可以直接比较用户输入密码和在数据库中保存的密码，无需应用

crypt（）

现在将代码更改为

        public function authenticate()
        {
            $record = User::model()->findByAttributes(array('username' => $this->username));
            if ($record === null)
                $this->errorCode = self::ERROR_USERNAME_INVALID;
            else if (trim($this->password)!== $record->password)
                $this->errorCode = self::ERROR_PASSWORD_INVALID;
            else
            {
                $this->_id = $record->id;
                $this->setState('title', $record->title);
                $this->errorCode = self::ERROR_NONE;
            }
            return !$this->errorCode;
        }

您是如何将密码保存在db中的？你加密了吗？没有。密码是纯文本的。我只是执行了mysql插入命令。我做错了吗？我试过了，但出了差错。属性“User.title”未定义。确定这意味着登录查询运行良好，现在我将编辑标题问题的答案。请确保用户表中有标题列，否则设置public$title；到用户模型类的顶部
        public function authenticate()
        {
            $record = User::model()->findByAttributes(array('username' => $this->username));
            if ($record === null)
                $this->errorCode = self::ERROR_USERNAME_INVALID;
            else if (trim($this->password)!== $record->password)
                $this->errorCode = self::ERROR_PASSWORD_INVALID;
            else
            {
                $this->_id = $record->id;
                $this->setState('title', $record->title);
                $this->errorCode = self::ERROR_NONE;
            }
            return !$this->errorCode;
        }