Php 以倒计时代码显示今天
嗨,如果给定日期是今天,我想显示今天,否则显示倒计时 这就是我到目前为止所尝试的…它永远不会显示任何东西…我做错了什么Php 以倒计时代码显示今天,php,date,countdown,Php,Date,Countdown,嗨,如果给定日期是今天,我想显示今天,否则显示倒计时 这就是我到目前为止所尝试的…它永远不会显示任何东西…我做错了什么 $d1 = new DateTime(); // now $d2 = new DateTime('2018-01-07'); // set the date +1 to compensate for 1-day $diff = $d2->diff($d1); list($y,$m,$d) = explode('-', $diff->format('%y-
$d1 = new DateTime(); // now
$d2 = new DateTime('2018-01-07'); // set the date +1 to compensate for 1-day
$diff = $d2->diff($d1);
list($y,$m,$d) = explode('-', $diff->format('%y-%m-%d'));
if ($d1 < $d2) {
$months = $y*12 + $m;
$weeks = floor($d/7);
$days = $d%7;
if($diff==0)
{
echo 'today';
}
else
{
printf('Countdown To Event : ');
if ($months) {printf('%d month%s ', $months, $months>1?'s':'');}
if ($weeks) {printf('%d week%s ', $weeks, $weeks>1?'s':'');}
if ($days) {printf('%d day%s ', $days, $days>1?'s':'');}
}
}
$d1=new DateTime();//现在
$d2=新日期时间('2018-01-07');//设置日期+1以补偿1天
$diff=$d2->diff($d1);
列表($y,$m,$d)=分解('-',$diff->格式(“%y-%m-%d”);
如果($d1<$d2){
$months=$y*12+m;
$weeks=底价($d/7);
$days=$d%7;
如果($diff==0)
{
回声“今天”;
}
其他的
{
printf(“事件倒计时:”);
如果($months){printf('%d个月%s',$months,$months,$months>1?'s':'';}
如果($weeks){printf(“%d周%s”,$weeks,$weeks,$weeks>1?'s':”;}
如果($days){printf('%d天%s',$days,$days,$days>1?'s':'';}
}
}
您不正确地使用了DateInteval对象
$d1 = new DateTime(); // now
$d2 = new DateTime('2018-01-07'); // set the date +1 to compensate for 1-day
// Object of DateInterval class
$diff = $d2->diff($d1);
// Difference in days
$d = $diff->days;
if (! $d) {
echo 'today';
}
else {
$months = $diff->m;
$days = $diff->d;
printf('Countdown To Event : ');
if ($months) {printf('%d month%s ', $months, $months>1?'s':'');}
// if ($weeks) {printf('%d week%s ', $weeks, $weeks>1?'s':'');}
if ($days) {printf('%d day%s ', $days, $days>1?'s':'');}
}
您错误地使用了DateInteval对象
$d1 = new DateTime(); // now
$d2 = new DateTime('2018-01-07'); // set the date +1 to compensate for 1-day
// Object of DateInterval class
$diff = $d2->diff($d1);
// Difference in days
$d = $diff->days;
if (! $d) {
echo 'today';
}
else {
$months = $diff->m;
$days = $diff->d;
printf('Countdown To Event : ');
if ($months) {printf('%d month%s ', $months, $months>1?'s':'');}
// if ($weeks) {printf('%d week%s ', $weeks, $weeks>1?'s':'');}
if ($days) {printf('%d day%s ', $days, $days>1?'s':'');}
}
这应该可以做到:
<?php
$today = new DateTime();
$date = (new DateTime())->add(new DateInterval('P1D'));
if ($today->format('Y-m-d') === $date->format('Y-m-d')) {
echo 'TODAY';
} else {
$d = $today->diff($date);
$result = '';
if ($d->years > 1) {
$result .= $d->years.' Years | ';
} else if ($d->years == 1) {
$result .= '1 Year | ';
} else {
$result .= '0 Years | ';
}
if ($d->months > 1) {
$result .= $d->months.' Months | ';
} else if ($d->months == 1) {
$result .= '1 Month | ';
} else {
$result .= '0 Months | ';
}
if ($d->days > 1) {
$result .= $d->days.' Days';
} else if ($d->days == 1) {
$result .= '1 Day';
} else {
$result .= '0 Days';
}
echo $result;
}
?>
工作演示。这应该可以做到:
<?php
$today = new DateTime();
$date = (new DateTime())->add(new DateInterval('P1D'));
if ($today->format('Y-m-d') === $date->format('Y-m-d')) {
echo 'TODAY';
} else {
$d = $today->diff($date);
$result = '';
if ($d->years > 1) {
$result .= $d->years.' Years | ';
} else if ($d->years == 1) {
$result .= '1 Year | ';
} else {
$result .= '0 Years | ';
}
if ($d->months > 1) {
$result .= $d->months.' Months | ';
} else if ($d->months == 1) {
$result .= '1 Month | ';
} else {
$result .= '0 Months | ';
}
if ($d->days > 1) {
$result .= $d->days.' Days';
} else if ($d->days == 1) {
$result .= '1 Day';
} else {
$result .= '0 Days';
}
echo $result;
}
?>
工作演示。这是一段简短的代码,可能会解决您的问题。请尝试以下操作:-
<?php
$d1 = date("Y-m-d");
$d2 = '2018-01-06';
if(strtotime($d1) == strtotime($d2) )
{
echo 'today';
}
else
{
printf('Countdown To Event : ');
}?>
这是一段简短的代码,可能会解决您的问题。请尝试以下方法:-
<?php
$d1 = date("Y-m-d");
$d2 = '2018-01-06';
if(strtotime($d1) == strtotime($d2) )
{
echo 'today';
}
else
{
printf('Countdown To Event : ');
}?>
如果事件发生在明天,现在是21:00,那么在您的算法中是“今天”,如果事件发生在明天,现在是21:00,那么在您的算法中是“今天”