Php 尝试将文本字段中的数据插入数据库时出现MySQL错误
尝试从我的网站将数据插入数据库时,我遇到此错误:Php 尝试将文本字段中的数据插入数据库时出现MySQL错误,php,mysql,Php,Mysql,尝试从我的网站将数据插入数据库时,我遇到此错误: Error: INSERT INTO newtask (new_category, new_department, new_required, new_name, new_address, new_contact, new_email, new_logged, new_description) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?) You have an error in your SQL syntax; c
Error: INSERT INTO newtask (new_category, new_department, new_required,
new_name, new_address, new_contact, new_email, new_logged, new_description)
VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?)
You have an error in your SQL syntax; check the manual that corresponds to
your
MySQL server version for the right syntax to use near '?, ?, ?, ?, ?, ?, ?,
?,
?)' at line 1
这是我的密码:
<?php
$servername = 'localhost';
$username = 'root';
$password = '';
$dbname = 'tasks_db';
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO newtask (new_category, new_department, new_required,
new_name, new_address, new_contact, new_email, new_logged, new_description)
VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?)";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
不知道我做错了什么 这是一个已准备好的语句,因此您需要准备它,绑定您的值,然后执行它:
$stmt = $conn->prepare("INSERT INTO newtask (new_category, new_department, new_required,
new_name, new_address, new_contact, new_email, new_logged, new_description)
VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?)");
// One "s" per placeholder value, plus one value per "s" after
$stmt->bind_param("sssssssss", $new_category, $new_department, ...);
if ($stmt->execute()) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$stmt=$conn->prepare(“插入新任务(需要新任务类别、新部门、新任务),
新名称、新地址、新联系人、新电子邮件、新日志、新描述)
数值(?,,,,,,,,,,,,,,,,,)”;
//每个占位符值一个“s”,之后每个“s”加一个值
$stmt->bind_参数(“SSS”、$new_category、$new_department、…);
如果($stmt->execute()){
echo“新记录创建成功”;
}否则{
echo“Error:”.$sql.“
”$conn->Error;
}
其中,$new\u category
是进入该列的任何值,依此类推。
这一切都包括在我的报告中
错误在于您试图运行一个带有占位符值且没有数据的SQL查询<代码>?在MySQL中不是有效值。在驱动程序级别,它被用
prepare
生成的语句上的bind_param
操作所取代。query
函数按原样执行代码,不做任何更改。请尝试摆脱用不必要的东西(如==true
)将代码弄乱的习惯。许多函数被设计为返回逻辑上为真或假的值,因此这是多余的。应该替换所有?
占位符的变量在哪里?谢谢,现在它更有意义了。然而,这就是我现在得到的错误“未定义变量:sql…”在第25行“echo”中,出现问题。请稍后再试。“$sql。“”$连接->错误;'因为在这段代码中,
$sql
是被分解出来的,所以只需将其从echo
语句中删除即可。连接错误应包含调试此错误所需的任何相关详细信息。注意:在生产环境中回显原始错误是一种非常危险的做法。试着把这些记录下来。