Php 使用jquery仅从表中的一列筛选多个值
我想使用jquery使用multiple-select筛选表中的特定列,其中用户可以选择多个值。 以下是HTML和PHP代码:Php 使用jquery仅从表中的一列筛选多个值,php,jquery,html,mysql,Php,Jquery,Html,Mysql,我想使用jquery使用multiple-select筛选表中的特定列,其中用户可以选择多个值。 以下是HTML和PHP代码: <table id="simple-table" class="table table-striped table-bordered table-hover"> <thead> <tr> <th>Codice Pezzo</th>
<table id="simple-table" class="table table-striped table-bordered table-hover">
<thead>
<tr>
<th>Codice Pezzo</th>
<th>Descrizione</th>
<th class="center">Fornitore
<div class="col-sm-12">
<select multiple="multiple" class="chosen-select form-control tag-input-style" id="fornitore-select" data-placeholder="Scegli un fornitore..." name="fornitore[]"><option value=""> </option><?php
// esecuzione della query
$query_fornitore = "SELECT p.Marca FROM pezzi p INNER JOIN distinte d ON (d.ID_Pezzo = p.ID_Pezzo) INNER JOIN ordini o ON (o.ID_Impianto = d.ID_Impianto) WHERE o.Data_Consegna >= '".$_GET["data1"]."' AND o.Data_Consegna <= '".$_GET["data2"]."' AND o.Elaborato = 0 GROUP BY p.Marca;";
$result_fornitore = @mysqli_query($conn, $query_fornitore);
// controllo sul numero dei record coinvolti
if(@mysqli_num_rows($result_fornitore)!=0)
{
// risultato sotto forma di array asscociativo
while($row_fornitore = mysqli_fetch_array($result_fornitore, MYSQLI_ASSOC))
{
echo "<option value=\"".$row_fornitore["Marca"]."\">".$row_fornitore["Marca"]."</option>";
}
}
?></select>
</div>
</th>
<th>Quantità</th>
</tr>
</thead>
<tbody id="body-fornitore">
<?php
if(isset($_GET["ordini_materiali"]) && isset($_GET["data1"]) && isset($_GET["data2"])):
$query_distinta = "SELECT d.ID_Pezzo, p.Descrizione, p.Marca, SUM(d.Quantita), o.Quantita FROM ordini o INNER JOIN distinte d ON (d.ID_Impianto = o.ID_Impianto) INNER JOIN pezzi p ON (p.ID_Pezzo = d.ID_Pezzo) WHERE o.Data_Consegna >= '".$_GET["data1"]."' AND o.Data_Consegna <= '".$_GET["data2"]."' AND o.Elaborato = 0 GROUP BY p.ID_Pezzo;";
$result_distinta = @mysqli_query($conn, $query_distinta);
while($row_distinta = mysqli_fetch_array($result_distinta)): ?>
<tr>
<td><?php echo $row_distinta[0]; ?></td>
<td><?php echo $row_distinta[1]; ?></td>
<td class="row-fornitore"><?php echo $row_distinta[2]; ?></td>
<td><?php echo number_format($row_distinta[3]*$row_distinta[4],2,",","."); ?></td>
</tr>
<?php endwhile; endif; ?>
</tbody>
</table>
使用这种方法,当我选择过滤器考虑表中所有列的多个选项时,我只想过滤一个(具体来说是第三个)。
有办法吗?我快疯了 您正在处理:
#body-fornitore tr
这意味着所有行,而您希望处理第三列,即:
.row-fornitore
关于您正在从事的工作:
#body-fornitore tr
这意味着所有行,而您希望处理第三列,即:
.row-fornitore
关于我在发帖前试过了。它不再工作了。当我尝试从下拉列表中选择值时,行消失。我在发布问题之前尝试过。它不再工作了。当我尝试从下拉列表中选择值时,行消失。