Php 从JSON对象获取值

现在我想把dp_id的值分别分成两个数组，即数组（4,5）和数组（1,3）

试试这个

stdClass Object
(
    [form] => stdClass Object
        (
            [fieldsets] => Array
                (
                    [0] => stdClass Object
                        (
                            [fieldset_name] => name_1
                            [datapoints] => Array
                                (
                                    [0] => stdClass Object
                                        (
                                            [dp_id] => 4
                                        )

                                    [1] => stdClass Object
                                        (
                                            [dp_id] => 5
                                        )
                                )

                        )

                    [1] => stdClass Object
                        (
                            [fieldset_name] => name_2
                            [datapoints] => Array
                                (
                                    [0] => stdClass Object
                                        (
                                            [dp_id] => 1
                                        )

                                    [1] => stdClass Object
                                        (
                                            [dp_id] => 3
                                        )

                                )

                        )

                )

        )

)

$object->form['fieldset'][1]->datapoints[1]

---

json从何而来？你有什么数据？它正在返回数组（3,1,4,5），但我希望作为数组（4,5）和数组（1,3），代码应该输出数组（4,5）和数组（1,3）。。。你需要在var_倾卸线做点什么。您可以将其存储在其他变量中进行处理。 $object->form['fieldsets'][1]->datapoints[1]

foreach($object->form->fieldsets as $fieldset) {
    $dp_ids = array();
    foreach($fieldset->datapoints as $datapoint)
        $dp_ids[] = $datapoint->dp_id;
    var_dump($dp_ids);
}