Php Laravel返回错误的数据库列名以保存数据

在Laravel迁移中，我有这样一行：

$table->tinyInteger('action_type')->index();

当我尝试在表中保存数据时，如以下代码所示：

ActionsLog::create([
    'account_id' => auth()->user()->id,
    'action_type' => 1,  //like
    'log', $ex->getMessage()
]);

laravel无法返回第三列，该列的名称为

action\u type

，我收到以下错误：

Column not found: 1054 Unknown column '1' in 'field list' (SQL: insert into `actions_logs` (`account_id`, `action_type`, `1`, `updated_at`, `created_at`) values (2, 1, SQLSTATE[42S22]: Column not found: 1054 Unknown column '1' in 'field list' (SQL: insert into `actions_logs` (`account_id`, `action_type`, `1`, `updated_at`, `created_at`) values (2, 1, Use of undefined constant ture - assumed 'ture' (this will throw an Error in a future version of PHP), 2018-07-11 07:50:18, 2018-07-11 07:50:18)), 2018-07-11 07:50:18, 2018-07-11 07:50:18))

我的迁移文件：

public function up()
{
    Schema::create('actions_logs', function (Blueprint $table) {
        $table->increments('id');
        $table->integer('account_id')->unsigned();
        $table->foreign('account_id')->references('id')->on('instagram_actions_histories')->onDelete('cascade');
        $table->tinyInteger('action_type')->index();
        $table->text('log');
        $table->timestamps();
    });
}

---

问题在于行

'log'，$ex->getMessage（）

。将此行中的

，

更改为

=>

。将代码替换为：

ActionsLog::create([
    'account_id' => auth()->user()->id,
    'action_type' => 1,
    'log' => $ex->getMessage()
]);

---

你不能那样创造

ActionsLog::create([
'account_id' => auth()->user()->id,
'action_type' => 1,
'log'=> $ex->getMessage()
]);

'log'=>$ex->getMessage（）----'log'，$ex->getMessage（）。在第一个键中=>value，在第二个值中，value