Php 尝试catch块不使用pdo语句和foreach
最近我鼓励PHP代码中出现奇怪的错误。这就像将PDOStatement对象与Php 尝试catch块不使用pdo语句和foreach,php,pdo,try-catch,pdostatement,Php,Pdo,Try Catch,Pdostatement,最近我鼓励PHP代码中出现奇怪的错误。这就像将PDOStatement对象与foreach(){}一起使用时,忽略了内部try{}catch(){}块。以下是触发此行为的测试代码: <?php /* // THIS WORKS AS EXPECTED, JUST UNCOMMENT try{ for($i = 0; $i < 3; $i++){ try{ echo "\nTHROWING EXCEPTION\n\n";
foreach(){}
一起使用时,忽略了内部try{}catch(){}
块。以下是触发此行为的测试代码:
<?php
/*
// THIS WORKS AS EXPECTED, JUST UNCOMMENT
try{
for($i = 0; $i < 3; $i++){
try{
echo "\nTHROWING EXCEPTION\n\n";
throw new Exception("AAAAAAAAAAAAAAAAAAAAAAAAA");
echo "EXCETION THROWN (SHOULD NOT SHOW)\n";
}catch(Exception $err){
echo "========= INNER CATCH =========\n";
echo $err->getMessage() . "\n";
}
}
}catch(Exception $e){
echo "=========== OUTER CATCH ===========\n";
die($e->getMessage() . "\n");
}
die("\nEVERYTHING OK\n");
*/
$dsn = "mysql:dbname=test_pdo;host=localhost";
try {
$dbh = new PDO($dsn, 'root', "", array(PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8"));
$dbh->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC);
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$dbh->exec("
CREATE TABLE IF NOT EXISTS `test` (
`id` int(10) unsigned NOT NULL,
`name` varchar(255) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `name` (`name`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
");
$dbh->exec("TRUNCATE test");
$dbh->exec("
INSERT INTO test (id, name) VALUES
(1, 'JOHN DOE 1'), (2, 'JOHN DOE 2'),
(3, 'JOHN DOE 3'), (4, 'JOHN DOE 4')
");
echo "\nRECORDS CREATED\n";
$sth = $dbh->prepare("SELECT id FROM test WHERE id = ?");
foreach(array(2, 3, 4) as $id){
$sth->execute(array($id));
$i = 0;
foreach($sth as $row){
$num = $row['id'] - 1;
// this sql should throw 2300 error duplicate key
$sql = "UPDATE test SET name = 'JOHN DOE $num' WHERE id = {$row['id']}";
try{
echo "\nSENDING QUERY: $sql\n\n";
$dbh->exec($sql);
}catch(Exception $err){
$code = $err->getCode();
$msg = $err->getMessage();
//duplicate key error?
if($err->getCode() != "23000"){
echo "THROWING EXCEPTION FROM INNER CATCH.\n ERROR CODE: $code\n";
throw $err;
}
echo <<<TXT
============ GOOD CATCH ============
ERROR CODE: $code
ERROR MSG: $msg
SQL: $sql
TXT;
}
}
}
}catch(Exception $e){
$code = $e->getCode();
$msg = $e->getMessage();
echo <<<TXT
============ WRONG CATCH ===========
ERROR CODE: $code
ERROR MSG: $msg
TXT;
}
不知道为什么,但当我将foreach($sth作为$row){
更改为foreach($sth->fetchAll()作为$row){
一切都按预期进行:
RECORDS CREATED
SENDING QUERY: UPDATE test SET name = 'JOHN DOE 1' WHERE id = 2
============ GOOD CATCH ============
ERROR CODE: 23000
ERROR MSG: SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry 'JOHN DOE 1' for key 'name'
SQL: UPDATE test SET name = 'JOHN DOE 1' WHERE id = 2
SENDING QUERY: UPDATE test SET name = 'JOHN DOE 2' WHERE id = 3
============ GOOD CATCH ============
ERROR CODE: 23000
ERROR MSG: SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry 'JOHN DOE 2' for key 'name'
SQL: UPDATE test SET name = 'JOHN DOE 2' WHERE id = 3
SENDING QUERY: UPDATE test SET name = 'JOHN DOE 3' WHERE id = 4
============ GOOD CATCH ============
ERROR CODE: 23000
ERROR MSG: SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry 'JOHN DOE 3' for key 'name'
SQL: UPDATE test SET name = 'JOHN DOE 3' WHERE id = 4
我是否发现了一个bug或者我做错了什么?有人能证实我的行为吗?谢谢
//编辑
将PHP版本升级到5.3.10似乎可以解决此问题。Thx寻求帮助…不,从PDO返回的结果不是您可以直接迭代的内容。这不是PDO异常,当您尝试这样做时,它是PHP——它不是数组或具有迭代器的对象
获取时,它会创建一个在foreach循环中有效的数组。
PDOStatement
实现了可遍历的
(),因此它可以与foreach一起使用,还是我错了?
RECORDS CREATED
SENDING QUERY: UPDATE test SET name = 'JOHN DOE 1' WHERE id = 2
============ GOOD CATCH ============
ERROR CODE: 23000
ERROR MSG: SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry 'JOHN DOE 1' for key 'name'
SQL: UPDATE test SET name = 'JOHN DOE 1' WHERE id = 2
SENDING QUERY: UPDATE test SET name = 'JOHN DOE 2' WHERE id = 3
============ GOOD CATCH ============
ERROR CODE: 23000
ERROR MSG: SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry 'JOHN DOE 2' for key 'name'
SQL: UPDATE test SET name = 'JOHN DOE 2' WHERE id = 3
SENDING QUERY: UPDATE test SET name = 'JOHN DOE 3' WHERE id = 4
============ GOOD CATCH ============
ERROR CODE: 23000
ERROR MSG: SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry 'JOHN DOE 3' for key 'name'
SQL: UPDATE test SET name = 'JOHN DOE 3' WHERE id = 4