PHP在从JSON转换为stdClass、进行更改,然后再转换回JSON时遇到麻烦
因此,在一开始,在加载send_sms.php之前,我将此Json存储在数据库中:PHP在从JSON转换为stdClass、进行更改,然后再转换回JSON时遇到麻烦,php,arrays,json,stdclass,Php,Arrays,Json,Stdclass,因此,在一开始,在加载send_sms.php之前,我将此Json存储在数据库中: { "chats": { "chat": [{ "id": "1", "name": "Ethan Wilberforce", "messages": { "message": [{ "id": "1", "name": "Ethan Wilberforce",
{
"chats": {
"chat": [{
"id": "1",
"name": "Ethan Wilberforce",
"messages": {
"message": [{
"id": "1",
"name": "Ethan Wilberforce",
"text": "Hello how are you doing",
"time": "4:41"
}, {
"id": "2",
"name": "Qasim Iqbal",
"text": "Not bad. How about you?",
"time": "4:42"
}, {
"id": "3",
"name": "Ethan Wilberforce",
"text": "I'm not too bad myself.",
"time": "4:43"
}]
}
}, {
"id": "2",
"name": "Geoff Vahaaho",
"messages": {
"message": [{
"id": "1",
"name": "Geoff Vahaaho",
"text": "Hello how are you doing",
"time": "4:41"
}, {
"id": "2",
"name": "Qasim Iqbal",
"text": "Not bad. How about you?",
"time": "4:42"
}, {
"id": "3",
"name": "Geoff Vahaaho",
"text": "I'm not too bad myself.",
"time": "4:43"
}, {
"id": "4",
"name": "Qasim Iqbal",
"text": "Nice.",
"time": "4:43"
}]
}
}]
}
}
Json是完全有效的,没有错误。它存储了两个聊天记录,其中包含消息
下面是改变Json的PHP代码:
$data = $user->data;
$parsed_data = json_decode($data);
...
for($i = 0, $size = sizeof($parsed_data->chats->chat); $i < $size; ++$i) {
if($parsed_data->chats->chat[$i]->name == $to) {
$found = true;
$parsed_data->chats->chat[$i]->messages->message[sizeof($parsed_data->chats->chat[$i]->messages->message)] = new stdClass;
$parsed_data->chats->chat[$i]->messages->message[sizeof($parsed_data->chats->chat[$i]->messages->message)]->id = sizeof($parsed_data->chats->chat[$i]->messages->message);
$parsed_data->chats->chat[$i]->messages->message[sizeof($parsed_data->chats->chat[$i]->messages->message)]->name = $user->name;
$parsed_data->chats->chat[$i]->messages->message[sizeof($parsed_data->chats->chat[$i]->messages->message)]->text = $message;
$parsed_data->chats->chat[$i]->messages->message[sizeof($parsed_data->chats->chat[$i]->messages->message)]->time = $time;
echo "done. ";
break;
}
}
您会注意到它确实添加到了“Ethan Wilberforce”聊天中,但是stdClass中的每个字符串都被转换为“message”数组中自己的数组项。我如何解决这个问题?非常感谢。您的问题是:
$parsed_data->chats->chat[$i]->messages->message[sizeof($parsed_data->chats->chat[$i]->messages->message)] = new stdClass;
$parsed_data->chats->chat[$i]->messages->message[sizeof($parsed_data->chats->chat[$i]->messages->message)]->id = sizeof($parsed_data->chats->chat[$i]->messages->message);
它基本上等于:
$array[$last] = new stdClass();
$array[$last+1] = "id";
$array[$last+2] = "name";
您不断追加新的数组/对象,因为您使用的sizeof(…)
总是比前一行大。这不是最后一个索引,而是大小。这是$lastindex+1
无论如何,您应该做的不是使用对象,而是一次附加一个数组及其所有属性:
$parsed_data->chats->chat[$i]->messages->message[] = array(
"id" => ...,
"name" => ...,
"time" => ...,
);
当您将关联数组编码回JSON时,它也将成为一个普通的
{…}
JSON对象组。我认为您需要逐个循环每个$parsed_data->chats->chat[$I]->messages->messages,因此在循环中循环并添加数据。虽然我不知道你想做什么。你能告诉我们你期望看到的结果吗?在发布这个问题后不久,我终于明白了。谢谢!:)使用(object)$array
,我将创建的数组转换为一个对象,然后消息[sizeof()]等于转换后的数组。
$parsed_data->chats->chat[$i]->messages->message[] = array(
"id" => ...,
"name" => ...,
"time" => ...,
);