Php 以数组形式返回SQL查询

reserva\u disponibilidade返回相同的数组（29），何时应该返回…29,30,31。。。 有办法解决这个问题吗

    function estoque($data, $dias, $tipo) {

        //Ajusta a data...
        $inicio = strtotime($data);
        $edia = date('d', $inicio); 
        $emes = date('m', $inicio);
        $eano = date('Y', $inicio);

        //Conecta ao db...
        $db = new DBConfig();
        $db->config();
        $db->conn();

        //Arrays
        $smarty_array = array();
        $smarty_data_array = array();

        $query_quartos = mysql_query("SELECT * FROM quartos AS quartos 
                                        INNER JOIN tipos AS tipos 
                                        LEFT JOIN reservas AS reservas 
                                        ON quartos.quarto_tipo = tipos.tipo_id
                                        AND quartos.quarto_numero = reservas.reserva_quarto_id
                                        WHERE quartos.quarto_tipo = '".$tipo."'
                                        GROUP BY quartos.quarto_id HAVING Count(*) >= 1") or die(mysql_error());
        while($row = mysql_fetch_assoc($query_quartos)){
            $quartoid = $row["quarto_id"];

            while($i <= $dias) {
                $today = strtotime(date('Y-m-d',mktime(0,0,0,date($emes),date($edia)+$i,date($eano))));
                $query = mysql_query("SELECT * FROM quartos AS quartos 
                              LEFT JOIN reservas AS reservas 
                              ON quartos.quarto_numero = reservas.reserva_quarto_id
                              AND ".$today." BETWEEN reservas.reserva_checkin AND reservas.reserva_checkout
                              WHERE quartos.quarto_id = '".$quartoid."'
                              GROUP BY quartos.quarto_id HAVING Count(*) >= 1") or die(mysql_error());
                while($rowe = mysql_fetch_assoc($query)){
                    if (empty($rowe["reserva_status"])) {
                        $rowe["reserva_status"] = "0";
                    }
                    $smarty_data_array[] = $rowe["reserva_status"];
                }
                $i++;
            }

            $row["reserva_disponibilidade"] = $smarty_data_array;
            $smarty_array[] = $row;
        }

        $db->close();
        return $smarty_array;
    }

---

这里的问题在于为$quartoid赋值的时间。如果只看这段代码：

while($row = mysql_fetch_assoc($query_quartos)){
        $quartoid = $row["quarto_id"];

        while($i <= $dias) {
            $today = strtotime(date('Y-m-d',mktime(0,0,0,date($emes),date($edia)+$i,date($eano))));
            $query = mysql_query("SELECT * FROM quartos AS quartos 
                          LEFT JOIN reservas AS reservas 
                          ON quartos.quarto_numero = reservas.reserva_quarto_id
                          AND ".$today." BETWEEN reservas.reserva_checkin AND reservas.reserva_checkout
                          WHERE quartos.quarto_id = '".$quartoid."'
                          GROUP BY quartos.quarto_id HAVING Count(*) >= 1") or die(mysql_error());
            while($rowe = mysql_fetch_assoc($query)){
                if (empty($rowe["reserva_status"])) {
                    $rowe["reserva_status"] = "0";
                }
                $smarty_data_array[] = $rowe["reserva_status"];
            }
            $i++;
        }

while（$row=mysql\u fetch\u assoc（$query\u quartos））{
$quartoid=$row[“quarto_id”]；
然而，太长了，读不下去了，不管怎样，这是什么：<代码> $RO[ [ RealvaDeSosiBidiIDe] ]=$smarty_data_array；

它们是否应该反转？这样，您就可以将$row键分配给整个smart_data_array。。如果我错了，我有点累了，有点困了。LOLI认为这是正确的，数据返回正确，但正在重复……我想说的一件事是，将SQL查询操作放入循环中？如果可以避免的话，这是个坏主意。同上用于时间戳生成逻辑。时间戳没有（或至少不应该）在循环过程中进行更改，因此您可以在进入循环之前只生成一次。至于SQL查询，使用IN而不是=意味着您可以匹配字段的值列表，而不是单个值。您可以使用循环来构建列表，然后运行单个查询来获取所有数据。这几乎肯定会快得多。我没有sucess之前只需要一个查询，但这是一个好主意。

while($row = mysql_fetch_assoc($query_quartos)){
        $quartoid = $row["quarto_id"];

        while($i <= $dias) {
            $today = strtotime(date('Y-m-d',mktime(0,0,0,date($emes),date($edia)+$i,date($eano))));
            $query = mysql_query("SELECT * FROM quartos AS quartos 
                          LEFT JOIN reservas AS reservas 
                          ON quartos.quarto_numero = reservas.reserva_quarto_id
                          AND ".$today." BETWEEN reservas.reserva_checkin AND reservas.reserva_checkout
                          WHERE quartos.quarto_id = '".$quartoid."'
                          GROUP BY quartos.quarto_id HAVING Count(*) >= 1") or die(mysql_error());
            while($rowe = mysql_fetch_assoc($query)){
                if (empty($rowe["reserva_status"])) {
                    $rowe["reserva_status"] = "0";
                }
                $smarty_data_array[] = $rowe["reserva_status"];
            }
            $i++;
        }