Php 新手在使用ASIHTTPRequest上传文件时遇到问题

我真的，真的，真的需要一些帮助。我到处都看了一些关于使用ASIFormDataRequest上传照片的详细文档（针对傻瓜）。有人能通过我给我一条生命线吗

这是我所拥有的，虽然我知道我可能离这很远

照相机

#import <UIKit/UIKit.h>
@class ASIFormDataRequest; 

...

这是我收到的剧本

$dir_dest = 'uploads/';
ob_start();
print_r($_FILES);
$test = ob_get_contents();
ob_end_clean();
$db->insert('connecttest', array('ts'=>date('Y-m-d H:i:s'), 'tempfield'=>$test))->execute();

这是我得到的结果

Array
(
    [(null)] => Array
        (
            [name] => (null)
            [type] => (null)
            [tmp_name] => C:\Windows\Temp\phpCFF0.tmp
            [error] => 0
            [size] => 0
        )

)

---

请帮助：（

我遇到了类似的问题，我使用

UIImage *im = [info objectForKey:@"UIImagePickerControllerOriginalImage"] ;
UIGraphicsBeginImageContext(CGSizeMake(320,480)); 
[im drawInRect:CGRectMake(0, 0,320,480)];
newImage = UIGraphicsGetImageFromCurrentImageContext(); 
UIGraphicsEndImageContext();
NSData* imageData=UIImageJPEGRepresentation(newImage, 0.5); 

当它开始工作时，拍摄的图像的高度和宽度将超过2000x2000，所以缩小它并尝试一下

[request setData:imageData withFileName:@"photo.jpg" andContentType:@"image/jpeg" forKey:@"file"];

这是php脚本

$filename="uploaded";
$target_path = "uploads/";
$target_path = $target_path .$filename.".jpg"; 
if(move_uploaded_file($_FILES['file']['tmp_name'], $target_path)) {
echo "uploaded an image";
} else{
    echo "There was an error uploading the file, please try again!";
}

$filename="uploaded";
$target_path = "uploads/";
$target_path = $target_path .$filename.".jpg"; 
if(move_uploaded_file($_FILES['file']['tmp_name'], $target_path)) {
echo "uploaded an image";
} else{
    echo "There was an error uploading the file, please try again!";
}