Php 从输入类型日期传递的日期似乎为空,输出..1970-01-01

Php 从输入类型日期传递的日期似乎为空,输出..1970-01-01,php,html,jquery,forms,Php,Html,Jquery,Forms,我有一个表。我想将输入类型日期更新为表数据。我想将其传递给php form intermediate.php。但是空值似乎被传递,输出似乎是1970-01-01,这意味着数据没有被传递 <form method="" action="intermediate.php"> <table id="updatetable"> </table> </form>

我有一个表。我想将输入类型日期更新为表数据。我想将其传递给php form intermediate.php。但是空值似乎被传递,输出似乎是
1970-01-01
,这意味着数据没有被传递

 <form method="" action="intermediate.php">
   <table id="updatetable">
     
    </table>
  </form>
    //Jquery added here
    <script>
     var today = new Date();
     var dd = String(today.getDate()).padStart(2, '0');
     var mm = String(today.getMonth() + 1).padStart(2, '0'); //January is 0!
     var yyyy = today.getFullYear();
    
     today = yyyy + '-' + mm + '-' + dd;
     var i;
     for(i=0;i<5;i++){
    updatetabledata += 
    '<td><input type="date"  id="vazhipadudate"'+i+'" 
    name="vazhipadudate' + i + ' " min="' + today + '"/>
     </td>';
   }
    $("#updatetable").empty().append(updatetabledata);
    </script>

我在主文件中做了一些更改。 添加方法:post,在js中传递值属性中的今天日期。 现在它可以正常工作了

index.php

<form method="post" action="intermediate.php">
       <table id="updatetable">
         
        </table>
        <input type="submit" name="">
    </form>
    //JQuery Link here...
    <script>
     var today = new Date();
     var dd = String(today.getDate()).padStart(2, '0');
     var mm = String(today.getMonth() + 1).padStart(2, '0'); //January is 0!
     var yyyy = today.getFullYear();
    
     today = yyyy+ '-' + mm + '-' + dd;
     var i;
     var updatetabledata = "";
     for(i=0;i<5;i++){
        updatetabledata += '<td><input type="date" id="vazhipadudate' + i + '" name="vazhipadudate[]" min="' + today + '" value="' + today + '"></td>';
   }
    $("#updatetable").empty().append(updatetabledata);
    </script>

我不明白,你把你的输入命名为
vazhipadudate
,然后你期望
$\u POST[“$date”]
(注意键名中的$),而且它似乎不是你所有的?请看@konrados$date='vazhipadudate'。$I你的输入名称后面有空格!还有,为什么不
name=“vazhipadudate[]”“
?。我仍在获得输出,因为现在的时间是…..选择的日期是…..1970-01-01。我想要选择的日期。这是否通过了@Mohit的选择日期Prajapati@soman拉杰,是的,现在检查一下。再更新一些东西。
The time now is.....Selected Date is..........1970-01-01
The time now is.....Selected Date is..........1970-01-01
The time now is.....Selected Date is..........1970-01-01
The time now is.....Selected Date is..........1970-01-01
The time now is.....Selected Date is..........1970-01-01
<form method="post" action="intermediate.php">
       <table id="updatetable">
         
        </table>
        <input type="submit" name="">
    </form>
    //JQuery Link here...
    <script>
     var today = new Date();
     var dd = String(today.getDate()).padStart(2, '0');
     var mm = String(today.getMonth() + 1).padStart(2, '0'); //January is 0!
     var yyyy = today.getFullYear();
    
     today = yyyy+ '-' + mm + '-' + dd;
     var i;
     var updatetabledata = "";
     for(i=0;i<5;i++){
        updatetabledata += '<td><input type="date" id="vazhipadudate' + i + '" name="vazhipadudate[]" min="' + today + '" value="' + today + '"></td>';
   }
    $("#updatetable").empty().append(updatetabledata);
    </script>
<?php 
    for($i=0;$i<count($_POST['vazhipadudate']);$i++){
    echo "The time now is.....".date("Y-m-d").'&nbsp;';
    echo "Selected Date is..........".$_POST['vazhipadudate'][$i].'<br/>' ;
}
?>
The time now is.....2020-07-10 Selected Date is..........2020-07-14
The time now is.....2020-07-10 Selected Date is..........2020-07-21
The time now is.....2020-07-10 Selected Date is..........2020-07-12
The time now is.....2020-07-10 Selected Date is..........2020-07-13
The time now is.....2020-07-10 Selected Date is..........2020-07-15