google图表上的php变量
我有谷歌图表工作,但需要将变量传递给它的javascript生成器,我尝试在javascript中使用$var,但它不工作 我有:google图表上的php变量,php,variables,charts,Php,Variables,Charts,我有谷歌图表工作,但需要将变量传递给它的javascript生成器,我尝试在javascript中使用$var,但它不工作 我有: script type="text/javascript" src="https://www.gstatic.com/charts/loader.js"></script> <script type="text/javascript"> google.charts.load('current'
script type="text/javascript" src="https://www.gstatic.com/charts/loader.js"></script>
<script type="text/javascript">
google.charts.load('current', {'packages':['corechart']});
google.charts.setOnLoadCallback(drawChart);
function drawChart() {
var data = google.visualization.arrayToDataTable([
['Estrelas', 'Pontuação'],
['1 estrelas', $ums],
['2 estrelas', $doiss],
['3 estrelas', $tress],
['3 estrelas', $quatros],
['5 estrela', $cincos]
]);
var options = {
title: 'My Daily Activities'
};
var chart = new google.visualization.PieChart(document.getElementById('piechart'));
chart.draw(data, options);
}
</script>
scripttype=“text/javascript”src=”https://www.gstatic.com/charts/loader.js">
load('current',{'packages':['corechart']});
google.charts.setOnLoadCallback(drawChart);
函数绘图图(){
var data=google.visualization.arrayToDataTable([
[‘Estrelas’、‘Pontuação’],
[1埃斯特拉斯,$ums],
['2 estrelas',$doiss],
['3 estrelas',$tress],
['3 estrelas',$quatros],
['5 estrela',$cincos]
]);
变量选项={
标题:“我的日常活动”
};
var chart=new google.visualization.PieChart(document.getElementById('PieChart');
图表绘制(数据、选项);
}
尝试在其周围放置PHP标记,例如:
['1 estrelas',$ums]
变成['1 estrelas',]
,您必须封装PHP变量,如:
['1 estrelas', <? echo $ums?> ],
['1 estrelas',],
或者如果您的PHP配置接受短标记
['1 estrelas', <?= $ums ?> ],
['1 estrelas',],
这个问题至少有4个重复:stks它工作得很好自从PHP5.4及更高版本以来,您可以使用tks它工作得很好