Php Websocket握手错误

我正在尝试在我的xampp安装中执行此操作

当我进入shell并键入php-qhtdocs\socket\server\startDeamon.php时，我得到了这个

2012-10-17 08:42:11 System: Socket Resource id #7 created.
2012-10-17 08:42:11 System: Socket bound to localhost:8000.
2012-10-17 08:42:11 System: Start listening on Socket.

Strict Standards: Only variables should be passed by reference in C:\xampp\htdoc
s\socket\server\socketWebSocket.class.php on line 35

Strict Standards: Only variables should be passed by reference in C:\xampp\htdoc
s\socket\server\socketWebSocket.class.php on line 35
2012-10-17 08:42:31 WebSocket: Resource id #8 disconnected!

Strict Standards: Only variables should be passed by reference in C:\xampp\htdoc
s\socket\server\socketWebSocket.class.php on line 35

Strict Standards: Only variables should be passed by reference in C:\xampp\htdoc
s\socket\server\socketWebSocket.class.php on line 35

可能是什么问题，代码是否旧

这是socketWebSocket.class.php的第35行

$num_sockets = socket_select($changed_sockets,$write=NULL,$exceptions=NULL,NULL);

尝试：

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张贴代码的第35行。但我会重新考虑在websockets中使用nodejs+socket.io，而不是一个非常简单的基于PHP的实现。@ThiefMaster发布了代码。

$write=NULL;
$exceptions=NULL;
$num_sockets = socket_select($changed_sockets,$write,$exceptions,0);