如何从php数据库帖子中获取URL？

我有一个iOS应用程序，可以将图像发布到php页面，然后将其保存到数据库中

iOS代码如下所示：

- (BOOL)uploadImage:(NSData *)imageData filename:(NSString *)filename{

    NSLog(@"uploading");

    NSString *urlString = @"http://www.myserver.com/appsapce/assets/uploadPics.php";

    NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease];
    [request setURL:[NSURL URLWithString:urlString]];
    [request setHTTPMethod:@"POST"];

    NSString *boundary = @"0xKhTmLbOuNdArY";
    NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@",boundary];
    [request addValue:contentType forHTTPHeaderField: @"Content-Type"];

    NSMutableData *body = [NSMutableData data];

    [body appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]];

    //Set the filename
    [body appendData:[[NSString stringWithString:[NSString stringWithFormat:@"Content-Disposition: form-data; name=\"userfile\"; filename=\"%@\"\r\n",filename]] dataUsingEncoding:NSUTF8StringEncoding]];

    [body appendData:[@"Content-Type: application/octet-stream\r\n\r\n" dataUsingEncoding:NSUTF8StringEncoding]];

    //append the image data
    [body appendData:[NSData dataWithData:imageData]];

    [body appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]];

    [request setHTTPBody:body];

    NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
    NSString *returnString = [[[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding] autorelease];

    NSLog(@"returningOKString");

    return ([returnString isEqualToString:@"OK"]);
}

<?php
$uploaddir = 'photos/';
$file = basename($_FILES['userfile']['name']);
$uploadfile = $uploaddir . $file;

if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) {
    echo "OK";
} else {
    echo "ERROR";
}

?>

php如下所示：

- (BOOL)uploadImage:(NSData *)imageData filename:(NSString *)filename{

    NSLog(@"uploading");

    NSString *urlString = @"http://www.myserver.com/appsapce/assets/uploadPics.php";

    NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease];
    [request setURL:[NSURL URLWithString:urlString]];
    [request setHTTPMethod:@"POST"];

    NSString *boundary = @"0xKhTmLbOuNdArY";
    NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@",boundary];
    [request addValue:contentType forHTTPHeaderField: @"Content-Type"];

    NSMutableData *body = [NSMutableData data];

    [body appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]];

    //Set the filename
    [body appendData:[[NSString stringWithString:[NSString stringWithFormat:@"Content-Disposition: form-data; name=\"userfile\"; filename=\"%@\"\r\n",filename]] dataUsingEncoding:NSUTF8StringEncoding]];

    [body appendData:[@"Content-Type: application/octet-stream\r\n\r\n" dataUsingEncoding:NSUTF8StringEncoding]];

    //append the image data
    [body appendData:[NSData dataWithData:imageData]];

    [body appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]];

    [request setHTTPBody:body];

    NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
    NSString *returnString = [[[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding] autorelease];

    NSLog(@"returningOKString");

    return ([returnString isEqualToString:@"OK"]);
}

<?php
$uploaddir = 'photos/';
$file = basename($_FILES['userfile']['name']);
$uploadfile = $uploaddir . $file;

if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) {
    echo "OK";
} else {
    echo "ERROR";
}

?>

如何将发布照片的服务器URL返回到iOS应用程序

Thx而不是

回显“OK”使用
echo$uploadfile

我还看到您仅从iOS传递文件名
basename（$\u FILES['userfile']['name']）

正如您知道的iOS中的文件名一样，只需检查returnString。如果其
正常
，则表示路径如下

www.xyz.com/photos/fileNameIPassed

这里
fileNameIPassed=basename（$\u FILES['userfile']['name']）
为什么不返回url而不是简单地返回“OK”？然后在iOS应用程序中捕获请求。