将php/mysql列输出显示为行

我使用以下语法在PHP中显示MySQL查询：

 function get_dayssincecapture($db)  
  {    
    $result = $db->query("SELECT DATEDIFF(now(), sarrive)as days,count(loadnumber) as loads from v2loads where  adminstatus='captured' group by DATEDIFF(now(), sarrive) "); 
    return $result; 
  } 
  $dayssincecapture = get_dayssincecapture($db); 

显示语法：

<table border=1>
    <tr>
    <? while($row = $dayssincecapture->fetch(PDO::FETCH_ASSOC)) { ?>
    <td><? echo $row['days']; ?><br><? echo $row['loads']; ?></td>
    <? } ?>
    </tr>
</table>

这将产生下面的屏幕输出

如何通过表语法进行修改，以便将days字段作为行标题，将load字段作为表的第二行

所以我想要的是：

一如既往地感谢您，请尝试：

<?php
$dayssincecapture = get_dayssincecapture($db); 
$data = array('days' => array(), 'loads' => array());

while($row = $dayssincecapture->fetch(PDO::FETCH_ASSOC)) {
    $data['days'][]  = $row['days'];
    $data['loads'][] = $row['loads'];
}
?>

<table style="border: 1px solid #000">
    <tr>
        <td>Days</td>
        <?php foreach ( $data['days'] as $day ) { ?>
            <td><?php echo $day; ?></td>
        <?php } ?>
    </tr>
    <tr>
        <td>Loads</td>
        <?php foreach ( $data['loads'] as $load ) { ?>
            <td><?php echo $load; ?></td>
        <?php } ?>
    </tr>
</table>

天
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试试：

<?php
$dayssincecapture = get_dayssincecapture($db); 
$data = array('days' => array(), 'loads' => array());

while($row = $dayssincecapture->fetch(PDO::FETCH_ASSOC)) {
    $data['days'][]  = $row['days'];
    $data['loads'][] = $row['loads'];
}
?>

<table style="border: 1px solid #000">
    <tr>
        <td>Days</td>
        <?php foreach ( $data['days'] as $day ) { ?>
            <td><?php echo $day; ?></td>
        <?php } ?>
    </tr>
    <tr>
        <td>Loads</td>
        <?php foreach ( $data['loads'] as $load ) { ?>
            <td><?php echo $load; ?></td>
        <?php } ?>
    </tr>
</table>

天
荷载

如果您想在MySQL中执行这种类型的转换，那么您将旋转数据。MySQL没有pivot函数，但您可以使用聚合函数和

CASE

语句复制该函数：

select 
  count(case when DATEDIFF(now(), sarrive) = 1 then loadnumber end) as Day_1,
  count(case when DATEDIFF(now(), sarrive) = 2 then loadnumber end) as Day_2,
  count(case when DATEDIFF(now(), sarrive) = 3 then loadnumber end) as Day_3,
  count(case when DATEDIFF(now(), sarrive) = 4 then loadnumber end) as Day_4,
  count(case when DATEDIFF(now(), sarrive) = 5 then loadnumber end) as Day_5,
  count(case when DATEDIFF(now(), sarrive) = 6 then loadnumber end) as Day_6,
  count(case when DATEDIFF(now(), sarrive) = 7 then loadnumber end) as Day_7
from v2loads
where adminstatus='captured' 

---

您还可以在准备好的语句中编写此代码以动态创建此语句，因为值是未知的。

如果您希望在MySQL中执行这种类型的转换，那么您将旋转数据。MySQL没有pivot函数，但您可以使用聚合函数和

CASE

语句复制该函数：

select 
  count(case when DATEDIFF(now(), sarrive) = 1 then loadnumber end) as Day_1,
  count(case when DATEDIFF(now(), sarrive) = 2 then loadnumber end) as Day_2,
  count(case when DATEDIFF(now(), sarrive) = 3 then loadnumber end) as Day_3,
  count(case when DATEDIFF(now(), sarrive) = 4 then loadnumber end) as Day_4,
  count(case when DATEDIFF(now(), sarrive) = 5 then loadnumber end) as Day_5,
  count(case when DATEDIFF(now(), sarrive) = 6 then loadnumber end) as Day_6,
  count(case when DATEDIFF(now(), sarrive) = 7 then loadnumber end) as Day_7
from v2loads
where adminstatus='captured' 

您还可以在准备好的语句中编写此代码以动态创建此语句，因为值未知。

您可以尝试：

<?php

while($row = $dayssincecapture->fetch(PDO::FETCH_ASSOC)) {
    $days_row .= "<td>" . $row['days'] . "</td>";
    $loads_row .= "<td>" . $row['loads'] . "</td>";
}

?>
<table> 

  <tr>
    <td>Days</td>
    <?php echo $days_row; ?>
  </tr>
  <tr>
    <td>Loads</td>
    <?php echo $loads_row; ?>
  </tr>
</table>

天
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您可以尝试：

<?php

while($row = $dayssincecapture->fetch(PDO::FETCH_ASSOC)) {
    $days_row .= "<td>" . $row['days'] . "</td>";
    $loads_row .= "<td>" . $row['loads'] . "</td>";
}

?>
<table> 

  <tr>
    <td>Days</td>
    <?php echo $days_row; ?>
  </tr>
  <tr>
    <td>Loads</td>
    <?php echo $loads_row; ?>
  </tr>
</table>

天
荷载

您想要SQL解决方案还是php？谢谢@BlueFoots，对两者都很满意。谢谢，你想要SQL解决方案还是php？谢谢@bluefeet，对两者都很满意。谢谢，Awesome@hsz，感谢您的及时回复。非常棒的语法，谢谢。非常棒@hsz，感谢您的及时回复。很棒的语法，谢谢。