Php 显示选项中的错误答案
数据库表结构： 课时表（又名考试表） 问题表：Php 显示选项中的错误答案,php,html,mysql,mysqli,Php,Html,Mysql,Mysqli,数据库表结构： 课时表（又名考试表） 问题表： SessionId QuestionId OptionId 137 1 5 137 2 2 OptionId OptionType 1 A-C 2 A-D 3 A-E 4 A-F 5 A-G 6 A-H 7 A-I 8 A-J 9
SessionId QuestionId OptionId
137 1 5
137 2 2
OptionId OptionType
1 A-C
2 A-D
3 A-E
4 A-F
5 A-G
6 A-H
7 A-I
8 A-J
9 A-K
10 A-L
11 A-M
12 A-N
13 A-O
14 A-P
15 A-Q
16 A-R
17 A-S
18 A-T
19 A-U
20 A-V
21 A-W
22 A-X
23 A-Y
24 A-Z
25 True or False
26 Yes or No
AnswerId(auto) SessionId QuestionId Answer
200 137 1 B
201 137 1 D
202 137 2 F
203 137 2 A
204 137 2 C
SessionId QuestionId OptionId
137 1 5
137 2 2
OptionId OptionType
1 A-C
2 A-D
3 A-E
4 A-F
5 A-G
6 A-H
7 A-I
8 A-J
9 A-K
10 A-L
11 A-M
12 A-N
13 A-O
14 A-P
15 A-Q
16 A-R
17 A-S
18 A-T
19 A-U
20 A-V
21 A-W
22 A-X
23 A-Y
24 A-Z
25 True or False
26 Yes or No
AnswerId(auto) SessionId QuestionId Answer
200 137 1 B
201 137 1 D
202 137 2 F
203 137 2 A
204 137 2 C
SessionId QuestionId OptionId
137 1 5
137 2 2
OptionId OptionType
1 A-C
2 A-D
3 A-E
4 A-F
5 A-G
6 A-H
7 A-I
8 A-J
9 A-K
10 A-L
11 A-M
12 A-N
13 A-O
14 A-P
15 A-Q
16 A-R
17 A-S
18 A-T
19 A-U
20 A-V
21 A-W
22 A-X
23 A-Y
24 A-Z
25 True or False
26 Yes or No
AnswerId(auto) SessionId QuestionId Answer
200 137 1 B
201 137 1 D
202 137 2 F
203 137 2 A
204 137 2 C
$option = array();
$option[1]= array(A,B,C);
$option[2]= array(A,B,C,D);
$option[3]= array(A,B,C,D,E);
...
$option[23]= array(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y);
$option[24]= array(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z);
$option[25]= array(True,False);
$option[26]= array(Yes,No);
SessionId QuestionId OptionId
137 1 5
137 2 2
OptionId OptionType
1 A-C
2 A-D
3 A-E
4 A-F
5 A-G
6 A-H
7 A-I
8 A-J
9 A-K
10 A-L
11 A-M
12 A-N
13 A-O
14 A-P
15 A-Q
16 A-R
17 A-S
18 A-T
19 A-U
20 A-V
21 A-W
22 A-X
23 A-Y
24 A-Z
25 True or False
26 Yes or No
AnswerId(auto) SessionId QuestionId Answer
200 137 1 B
201 137 1 D
202 137 2 F
203 137 2 A
204 137 2 C
SELECT
q.QuestionContent,
o.OptionType,
q.NoofAnswers,
GROUP_CONCAT(DISTINCT Answer ORDER BY Answer SEPARATOR '') AS Answer,
r.ReplyType,
q.QuestionMarks
FROM Question q
LEFT JOIN Answer an
ON q.QuestionId = an.QuestionId
LEFT JOIN Reply r
ON q.ReplyId = r.ReplyId
LEFT JOIN Option_Table o
ON q.OptionId = o.OptionId
group by q.QuestionContent
| QUESTIONCONTENT | OPTIONTYPE | NOOFANSWERS | ANSWER | REPLYTYPE | QUESTIONMARKS |
----------------------------------------------------------------------------------------
| Name these 2 flowers | A-F | 2 | C | Multiple | 5 |
| What is 2+2? | A-D | 1 | ABD | Single | 5 |
我想你需要
选项表的设计方式，解码OptionType
列以找出所有可能的答案需要一些非平凡的外部知识
（事实上，您在问题中没有提供足够的信息让我确切知道如何做到这一点；我可以猜测您向我展示的那些optionType
，但我不能确定是否存在或可能存在其他类型。）
最好用更简单的表替换（或至少扩充）该表，对于每个选项id
，该表只列出所有可能的选项，如下所示：
CREATE TABLE Options (
OptionId INTEGER NOT NULL,
OptionAnswer CHAR(1) NOT NULL, -- or whatever type Answer.Answer has
PRIMARY KEY (OptionId, OptionAnswer)
);
INSERT INTO Options VALUES
(1, 'A'), (1, 'B'), (1, 'C'),
(2, 'A'), (2, 'B'), (2, 'C'), (2, 'D'),
-- ...
(25, 'T'), (25, 'F'),
(26, 'Y'), (16, 'N');
SELECT
q.QuestionContent,
q.NoofAnswers,
GROUP_CONCAT(DISTINCT Answer ORDER BY Answer SEPARATOR '') AS RightAnswers,
GROUP_CONCAT(DISTINCT
CASE
WHEN Answer IS NULL THEN OptionAnswer
ELSE NULL
END
ORDER BY OptionAnswer SEPARATOR '') AS WrongAnswers,
r.ReplyType,
q.QuestionMarks
FROM Question q
LEFT JOIN Reply r
ON q.ReplyId = r.ReplyId
LEFT JOIN Options o
ON q.OptionId = o.OptionId
LEFT JOIN Answer an
ON q.QuestionId = an.QuestionId AND o.OptionAnswer = an.Answer
GROUP BY q.SessionId, q.QuestionId
// Do this (preferably) before looping over the rows:
$specialOptionTypes = array(
'Yes or No' => array( 'Y', 'N' ),
'True or False' => array( 'T', 'F' ),
);
// Do this for each row:
if ( array_key_exists( $row->OptionType, $specialOptionTypes ) ) {
$options = $specialOptionTypes[ $row->OptionType ];
} else if ( preg_match( '/^([A-Z])-([A-Z])$/', $row->OptionType, $match ) ) {
$options = range( $match[1], $match[2] );
} else {
// issue warning about unrecognized option type
$options = array();
}
$right = str_split( $row->Answer ); // or explode() on a delimiter, if any
$wrong = array_diff( $options, $right );
$row->WrongAnswers = implode( '', $wrong ); // if you actually want a string
然后，您可以通过以下查询找到每个问题的所有正确答案和错误答案：
CREATE TABLE Options (
OptionId INTEGER NOT NULL,
OptionAnswer CHAR(1) NOT NULL, -- or whatever type Answer.Answer has
PRIMARY KEY (OptionId, OptionAnswer)
);
INSERT INTO Options VALUES
(1, 'A'), (1, 'B'), (1, 'C'),
(2, 'A'), (2, 'B'), (2, 'C'), (2, 'D'),
-- ...
(25, 'T'), (25, 'F'),
(26, 'Y'), (16, 'N');
SELECT
q.QuestionContent,
q.NoofAnswers,
GROUP_CONCAT(DISTINCT Answer ORDER BY Answer SEPARATOR '') AS RightAnswers,
GROUP_CONCAT(DISTINCT
CASE
WHEN Answer IS NULL THEN OptionAnswer
ELSE NULL
END
ORDER BY OptionAnswer SEPARATOR '') AS WrongAnswers,
r.ReplyType,
q.QuestionMarks
FROM Question q
LEFT JOIN Reply r
ON q.ReplyId = r.ReplyId
LEFT JOIN Options o
ON q.OptionId = o.OptionId
LEFT JOIN Answer an
ON q.QuestionId = an.QuestionId AND o.OptionAnswer = an.Answer
GROUP BY q.SessionId, q.QuestionId
// Do this (preferably) before looping over the rows:
$specialOptionTypes = array(
'Yes or No' => array( 'Y', 'N' ),
'True or False' => array( 'T', 'F' ),
);
// Do this for each row:
if ( array_key_exists( $row->OptionType, $specialOptionTypes ) ) {
$options = $specialOptionTypes[ $row->OptionType ];
} else if ( preg_match( '/^([A-Z])-([A-Z])$/', $row->OptionType, $match ) ) {
$options = range( $match[1], $match[2] );
} else {
// issue warning about unrecognized option type
$options = array();
}
$right = str_split( $row->Answer ); // or explode() on a delimiter, if any
$wrong = array_diff( $options, $right );
$row->WrongAnswers = implode( '', $wrong ); // if you actually want a string
下面是一个示例（稍作修改以跳过示例表中未包含的列）
编辑：另一种解决方案是用PHP构建错误答案列表。例如，如果$row
是一个包含原始查询中的一行的对象（如返回的），则可能会计算如下错误答案：
CREATE TABLE Options (
OptionId INTEGER NOT NULL,
OptionAnswer CHAR(1) NOT NULL, -- or whatever type Answer.Answer has
PRIMARY KEY (OptionId, OptionAnswer)
);
INSERT INTO Options VALUES
(1, 'A'), (1, 'B'), (1, 'C'),
(2, 'A'), (2, 'B'), (2, 'C'), (2, 'D'),
-- ...
(25, 'T'), (25, 'F'),
(26, 'Y'), (16, 'N');
SELECT
q.QuestionContent,
q.NoofAnswers,
GROUP_CONCAT(DISTINCT Answer ORDER BY Answer SEPARATOR '') AS RightAnswers,
GROUP_CONCAT(DISTINCT
CASE
WHEN Answer IS NULL THEN OptionAnswer
ELSE NULL
END
ORDER BY OptionAnswer SEPARATOR '') AS WrongAnswers,
r.ReplyType,
q.QuestionMarks
FROM Question q
LEFT JOIN Reply r
ON q.ReplyId = r.ReplyId
LEFT JOIN Options o
ON q.OptionId = o.OptionId
LEFT JOIN Answer an
ON q.QuestionId = an.QuestionId AND o.OptionAnswer = an.Answer
GROUP BY q.SessionId, q.QuestionId
// Do this (preferably) before looping over the rows:
$specialOptionTypes = array(
'Yes or No' => array( 'Y', 'N' ),
'True or False' => array( 'T', 'F' ),
);
// Do this for each row:
if ( array_key_exists( $row->OptionType, $specialOptionTypes ) ) {
$options = $specialOptionTypes[ $row->OptionType ];
} else if ( preg_match( '/^([A-Z])-([A-Z])$/', $row->OptionType, $match ) ) {
$options = range( $match[1], $match[2] );
} else {
// issue warning about unrecognized option type
$options = array();
}
$right = str_split( $row->Answer ); // or explode() on a delimiter, if any
$wrong = array_diff( $options, $right );
$row->WrongAnswers = implode( '', $wrong ); // if you actually want a string
，基于您的示例查询输出。什么是函数中允许的\u在中？您如何知道问题的正确答案？@BarryChapman通过从答案表中进行选择，啊，我忘记发布查询来检查，请给我一点时间将其包括在内。您可以发布用于收集结果的SQL吗？您是否将正确答案存储在数据库中？以这种方式使用GROUP_CONCAT（）对真/假和是/否问题不起作用。如果选项类型是固定的，您始终可以自己创建额外的表，如果不允许您创建永久的表，则可以作为一个额外的表。您甚至可以在PHP中解析原始的Option\u表
条目，并基于它们创建临时表（这可能比在MySQL中创建临时表更容易）。我在我的答案中添加了一个PHP替代方案，请参见上文。酷酷的PHP替代方案将是我可以使用的。谢谢