使用php构建复杂的JSON
我需要从PHP构建一些JSON。JSON的结构并不简单:使用php构建复杂的JSON,php,json,Php,Json,我需要从PHP构建一些JSON。JSON的结构并不简单: { "new" : { "checkpoints" : [ { "id" : "businessidea", "name" : "business idea", "purpose" : "Form a business idea",
{
"new" : {
"checkpoints" :
[
{
"id" : "businessidea",
"name" : "business idea",
"purpose" : "Form a business idea",
"customer" :
{ "questions" :
[
{ "questionid" : "id1", "questiontitle": "Evaluate size of the market, likely growth vectors and estimate addressable size.", "answers" :
[
{"answertext" : "an answer here", "answerlink": "", "answers": [
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"}
]},
{"answertext" : "an answer here", "answerlink": "", "answers": [
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"}
]},
{"answertext" : "an answer here", "answerlink": "", "answers": [
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"}
]}
]
},
{ "questionid" : "id2","questiontitle": "Define the needs of the customers and the value we will deliver to the customers - customer pain and our solution", "answers" :
[
{"answertext" : "an answer here", "answerlink": "", "answers": [
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"}
]},
{"answertext" : "an answer here", "answerlink": "", "answers": [
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"}
]},
{"answertext" : "an answer here", "answerlink": "", "answers": [
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"}
]}
]
},
{ "questionid" : "id3","questiontitle": "Define the competitor landscape" , "answers" :
[
{"answertext" : "an answer here", "answerlink": "", "answers": [
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"}
]},
{"answertext" : "an answer here", "answerlink": "", "answers": [
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"}
]},
{"answertext" : "an answer here", "answerlink": "", "answers": [
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"},
{"answertext": "answer text here", "answerlink": "http://google.com"}
]}
]}
]
},
实现这一目标的最佳方式是什么?我是通过使用大量字符串连接来构建这个json,还是可以使用PHP内置的json工具?
<?php echo json_encode($yourArray); ?>
我是否通过使用大量字符串连接来构建这个json
不可以。永远不要通过将字符串混合在一起来构建JSON
或者使用PHP内置的JSON工具是否可行
<?php echo json_encode($yourArray); ?>
对
用PHP构建数据结构。具体如何做取决于首先从何处获取数据
完成后,将其传递。使用
json\u decode
,如果希望将其作为数组,则添加true
作为第二个参数。您从不使用字符串函数构建json
创建一个数组(或stdClass对象)并将其保存。使用数组来构造数据,然后使用json_encode将其转换为json 除非您正在为一种不存在好的JSON序列化程序的语言编写JSON序列化程序,否则根本没有可以接受的理由这样做。有些解决问题的方法是错误的。(和边缘的情况,如“我们需要它昨天,没有时间升级PHP到远程现代的东西”,应该尖叫和适当尽快与黑客识别为黑客)。使用字符串创建JSON不是最好的方式,您将强制PHP对字符串求值,以了解数据的类型,这是一个键,这就是数据。使用数组不需要进行评估,因为数组内部知道valuesOk的数据类型,如何在php中构建数据结构?我正在从数据库调用中获取数据。通过创建和分配
Array
s。